Symfony PHPUnit-注入依赖

Kev*_*vin 4 phpunit symfony lexikjwtauthbundle symfony4

我想测试这个TokenProvider

<?php

declare(strict_types=1);

namespace App\Services\Provider;

use App\Repository\UserRepository;
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;
use Lexik\Bundle\JWTAuthenticationBundle\Encoder\JWTEncoderInterface;
use Symfony\Component\Security\Core\Exception\BadCredentialsException;

/**
 * Class TokenProvider
 * @package App\Services\Provider
 */
class TokenProvider
{
    /** @var JWTEncoderInterface */
    private $JWTEncoder;
    /** @var UserPasswordEncoderInterface */
    private $passwordEncoder;
    /** @var UserRepository */
    private $userRepository;

    /**
     * TokenProvider constructor.
     *
     * @param JWTEncoderInterface          $JWTEncoder
     * @param UserPasswordEncoderInterface $passwordEncoder
     * @param UserRepository               $userRepository
     */
    public function __construct(JWTEncoderInterface $JWTEncoder, UserPasswordEncoderInterface $passwordEncoder, UserRepository $userRepository)
    {
        $this->JWTEncoder = $JWTEncoder;
        $this->passwordEncoder = $passwordEncoder;
        $this->userRepository = $userRepository;
    }

    /**
     * @param string $email
     * @param string $password
     *
     * @return string
     * @throws \Lexik\Bundle\JWTAuthenticationBundle\Exception\JWTEncodeFailureException
     */
    public function getToken(string $email, string $password): string
    {
        $user = $this->userRepository->findOneBy([
            'email' => $email,
        ]);

        if (!$user) {
            throw new NotFoundHttpException('User Not Found');
        }

        $isValid = $this->passwordEncoder->isPasswordValid($user, $password);
        if (!$isValid) {
            throw new BadCredentialsException();
        }

        return $this->JWTEncoder->encode([
            'email' => $user->getEmail(),
            'exp' => time() + 3600 // 1 hour expiration
        ]);
    }
}
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这是我的测试。还没结束

我想注入,JWTEncoderInterface $encoderUserPasswordEncoder $passwordEncoder在我的testGetToken()

class TokenProviderTest extends TestCase
{
    /**
     * @throws \Lexik\Bundle\JWTAuthenticationBundle\Exception\JWTEncodeFailureException
     */
    public function testGetToken()
    {
        $this->markTestSkipped();

        $JWTEncoder = //TODO;
        $passwordEncoder = //TODO;

        $tokenProvider = new TokenProvider(
            $JWTEncoder,
            $passwordEncoder,
            new class extends UserRepository{
                public function findOneBy(array $criteria, array $orderBy = null)
                {
                    return (new User())
                        ->setEmail('kevin@leroi.com')
                        ->setPassword('password')
                    ;
                }
            }
        );

        $token = $tokenProvider->getToken('kevin@leroi.com', 'password');
        $this->assertEquals(true, $token);
    }
}
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在TestCase中执行此操作的好方法是什么?

我不想模拟这两个服务,因为我想用LexikJWTAuthenticationBundle检查我的令牌是否有效

Ell*_*Brl 7

我建议您扩展KernelTestCase并在setUp()函数中获取依赖,如下所示:

use Symfony\Bundle\FrameworkBundle\Test\KernelTestCase;

class TokenProviderTest extends KernelTestCase
{
private $jWTEncoder

protected function setUp()
{
   self::bootKernel();
   $this->jWTEncoder = self::$container->get('App\Services\TokenProvider');
}

public function testGetToken()
{
  //Your code
}
}
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可能对您有帮助:https : //symfony.com/doc/current/testing/doctrine.html#functional-testing


som*_*hpc 5

当我不断收到以下弃用警告时,我遇到了这个答案:

  1x: Since symfony/twig-bundle 5.2: Accessing the "twig" service directly from the container is deprecated, use dependency injection instead.
    1x in ExtensionTest::testIconsExtension from App\Tests\Templates\Icons
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我使用以下方法解决了这个问题:

static::bootKernel();
$container = self::$kernel->getContainer()->get('test.service_container');
$twig      = $container->get('twig');
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如本 Symfony 文档中所述