MVVM Light RelayCommand参数

Question

我在使用GalaSoft MVVM Light框架将参数传递给relaycommand时遇到问题.我知道mvvm light的relay命令的实现不使用lambda参数,所以我做了一些研究,并找到了一种方法,人们通过做这样的事情来解决它:

public RelayCommand ProjMenuItem_Edit
{
    get
    {
        if (_projmenuItem_Edit == null)
        {
            //This should work....
            _projmenuItem_Edit = new RelayCommand(ProjEditNode);
        }
        return _projmenuItem_Edit;
    }
}

private void ProjEditNode(object newText)
{
    var str = newText as string;
    OrganLocationViewModel sel = 
        ProjectOrganLocationView.GetExtendedTreeView().GetTopNode();

    //Console.WriteLine(sel.OrganDisplayName);
    sel.OrganDisplayName = str;
}

但是,我一直在_projmenuItem_Edit = new RelayCommand(ProjEditNode);说错误Argument 1: cannot convert from 'method group' to 'System.Action'

我错过了什么？

Answer 1

我相信这会奏效:

_projmenuItem_Edit = new RelayCommand<object>((txt)=>ProjEditNode(txt));

- 编辑 -

您还需要使用类型定义RelayCommand:

例如

public RelayCommand<string> myCommand { get; private set; }
myCommand = new RelayCommand<string>((s) => Test(s));

private void Test(string s)
{
    throw new NotImplementedException();
}