这是我的剧本.我曾尝试但无法获得正确的结果.请给出一些建议,谢谢和欣赏.
function groupBy() {
var list = [{
"id": "009",
"Nm": "Model 1",
"pid": "adidas"
},
{
"id": "007",
"Nm": "Model 1",
"pid": "adidas"
},
{
"id": "006",
"Nm": "Model 1",
"pid": "adidas"
},
{
"id": "pm1",
"Nm": "Model 1",
"pid": "puma"
},
{
"id": "003",
"Nm": "Model 1",
"pid": "adidas"
},
{
"id": "pm5",
"Nm": "Model 1",
"pid": "puma"
},
{
"id": "aj1",
"Nm": "Model 1",
"pid": "nike"
},
{
"id": "aj2",
"Nm": "Model 1",
"pid": "nike"
}
];
var output = [];
for (var i = 0; i < list.length; i++) {
if (list[i].pid != undefined) {
output.push(list[i]);
}
}
console.log(output);
}
groupBy();Run Code Online (Sandbox Code Playgroud)
一种选择是reduce进入由pids 索引的对象,其值为数组.在每次迭代时,如果数组不存在,则在相应的属性上创建数组,然后推送到该数组:
var list = [
{"id":"009","Nm":"Model 1","pid":"adidas"},
{"id":"007","Nm":"Model 1","pid":"adidas"},
{"id":"006","Nm":"Model 1","pid":"adidas"},
{"id":"pm1","Nm":"Model 1","pid":"puma"},
{"id":"003","Nm":"Model 1","pid":"adidas"},
{"id":"pm5","Nm":"Model 1","pid":"puma"},
{"id":"aj1","Nm":"Model 1","pid":"nike"},
{"id":"aj2","Nm":"Model 1","pid":"nike"}
];
console.log(
list.reduce((a, item) => {
const { pid } = item;
if (!a[pid]) a[pid] = [];
a[pid].push(item);
return a;
}, {})
);Run Code Online (Sandbox Code Playgroud)