c ++运算符重载

Question

//#include <string>
#include <iostream>
#include <string.h>
#include <stdio.h>
using namespace std;

template<class T, class X> class Obj{
T my_t;
X my_x;
public:
    Obj(T t, X x):my_t(t),my_x(x){}
     operator T() const {return my_t;}
};
int main()
{
    int iT;
    Obj<int, float> O(15,10.375);

    iT = O;
    cout << iT << endl;
    return O;
}

关于这一行:operator T() const {return my_t;} 这个运算符是否过载？但我不太明白哪个运营商超载了？谁能为我解释一下？谢谢!

Answer 1

是的,这是运营商重载.已经过载的运算符是要键入的转换运算符T.这是当您要求编译器将其转换Obj<T,X>为a 时调用的运算符T.