Gri*_*pal 9 javascript node.js async.js typescript node-request
我正在调用bitbucket API来获取repo中的所有文件.我已达到这样的程度,我可以获取repo中所有文件夹的列表,并对repo中的所有根文件夹进行第一次API调用,并获取所有文件夹的前1000个文件列表.
但问题是bitbucket api一次只能给我每个文件夹1000个文件.
我需要附加一个查询参数&start = nextPageStart并再次进行调用,直到它为null并且每个API的isLastPage为true.如何使用以下代码实现这一目标?
我从第一次调用api获得nextPageStart.请参阅下面的API响应.
下面是我到目前为止的代码.
任何帮助或指导表示赞赏.
来自每个文件夹调用的各个API的响应.
{
"values": [
"/src/js/abc.js",
"/src/js/efg.js",
"/src/js/ffg.js",
...
],
"size": 1000,
"isLastPage": false,
"start": 0,
"limit": 1000,
"nextPageStart": 1000
}
Run Code Online (Sandbox Code Playgroud)
函数,我进行异步调用以获取文件列表
export function getFilesList() {
const foldersURL: any[] = [];
getFoldersFromRepo().then((response) => {
const values = response.values;
values.forEach((value: any) => {
//creating API URL for each folder in the repo
const URL = 'https://bitbucket.abc.com/stash/rest/api/latest/projects/'
+ value.project.key + '/repos/' + value.slug + '/files?limit=1000';
foldersURL.push(URL);
});
return foldersURL;
}).then((res) => {
// console.log('Calling all the URLS in parallel');
async.map(res, (link, callback) => {
const options = {
url: link,
auth: {
password: 'password',
username: 'username',
},
};
request(options, (error, response, body) => {
// TODO: How do I make the get call again so that i can paginate and append the response to the body till the last page.
callback(error, body);
});
}, (err, results) => {
console.log('In err, results function');
if (err) {
return console.log(err);
}
//Consolidated results after all API calls.
console.log('results', results);
});
})
.catch((error) => error);
}
Run Code Online (Sandbox Code Playgroud)
我能够通过回调创建一个函数.
export function getFilesList() {
const foldersURL: any[] = [];
getFoldersFromRepo().then((response) => {
const values = response.values;
values.forEach((value: any) => {
//creating API URL for each folder in the repo
const URL = 'https://bitbucket.abc.com/stash/rest/api/latest/projects/'
+ value.project.key + '/repos/' + value.slug + '/files?limit=1000';
foldersURL.push(URL);
});
return foldersURL;
}).then((res) => {
// console.log('Calling all the URLS in parallel');
async.map(res, (link, callback) => {
const options = {
url: link,
auth: {
password: 'password',
username: 'username',
},
};
const myarray = [];
// This function will consolidate response till the last Page per API.
consolidatePaginatedResponse(options, link, myarray, callback);
}, (err, results) => {
console.log('In err, results function');
if (err) {
return console.log(err);
}
//Consolidated results after all API calls.
console.log('results', results);
});
})
.catch((error) => error);
}
function consolidatePaginatedResponse(options, link, myarray, callback) {
request(options, (error, response, body) => {
const content = JSON.parse(body);
content.link = options.url;
myarray.push(content);
if (content.isLastPage === false) {
options.url = link + '&start=' + content.nextPageStart;
consolidatePaginatedResponse(options, link, myarray, callback);
} else {
// Final response after consolidation per API
callback(error, JSON.stringify(myarray));
}
});
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
777 次 |
| 最近记录: |