Jus*_*oel 3 jestjs react-native
我正在尝试测试从 React NativeButton元素调用组件方法。
由于某种原因,除非我同时执行这两件事,否则测试会失败。
wrapper.find(Button).first().props().onPress();
wrapper.find(Button).first().simulate('press');
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如果我注释掉任何一行,测试就会失败,表明expect(instance.toggleEmailPasswordModal).toHaveBeenCalled();失败。
这是我的组件:
import React, { Component } from 'react';
import { Button, SafeAreaView, Text } from 'react-native';
import EmailPasswordModal from './EmailPasswordModal/EmailPasswordModal';
class Login extends Component {
state = {
emailPasswordModalVisible: false,
};
toggleEmailPasswordModal = () => {
console.log('TOGGLED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!');
const { emailPasswordModalVisible } = this.state;
this.setState({ emailPasswordModalVisible: !emailPasswordModalVisible });
};
render() {
const { emailPasswordModalVisible } = this.state;
return (
<SafeAreaView>
<EmailPasswordModal
visible={ emailPasswordModalVisible }
close={ this.toggleEmailPasswordModal }
/>
<Text>Login Screen!</Text>
<Button
onPress={ this.toggleEmailPasswordModal }
title="Login with Email and Password"
color="#841584"
accessibilityLabel="Login with Email and Password"
/>
</SafeAreaView>
);
}
}
export default Login;
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这是我的测试:
import React from 'react';
import ShallowRenderer from 'react-test-renderer/shallow';
import { shallow } from 'enzyme';
import { Button } from 'react-native';
import Login from './Login';
describe('Login Screen', () => {
describe('Snapshot Tests', () => {
it('renders the screen with default state', () => {
const renderer = new ShallowRenderer();
const props = {};
renderer.render(<Login { ...props } />);
expect(renderer.getRenderOutput()).toMatchSnapshot();
});
});
describe('Functional Tests', () => {
it('calls the toggleEmailPasswordModal method', () => {
const wrapper = shallow(<Login />);
const instance = wrapper.instance();
jest.spyOn(instance, 'toggleEmailPasswordModal');
wrapper.find(Button).first().props().onPress();
wrapper.find(Button).first().simulate('press');
expect(instance.toggleEmailPasswordModal).toHaveBeenCalled();
});
});
});
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奇怪的是,当测试运行时,输出显示“TOGGLED!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! !!!!!!!!!!!!” 由于组件中的日志记录,两次。
但是,如果我将其更改expect为:
expect(instance.toggleEmailPasswordModal).toHaveBeenCalledTimes(1);
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测试通过。
如果我将其更改expect为:
expect(instance.toggleEmailPasswordModal).toHaveBeenCalledTimes(2);
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测试失败,说toggleEmailPasswordModal只被调用了 1 次。
为什么我需要这两wrapper.find(Button)...行?我从未见过任何其他测试需要这两者。
谢谢,贾斯汀
我更新了我的测试如下:
it('calls the toggleEmailPasswordModal method', () => {
const wrapper = shallow(<Login />);
const instance = wrapper.instance();
jest.spyOn(instance, 'toggleEmailPasswordModal');
wrapper.find(Button).first().props().onPress();
wrapper.find(Button).first().simulate('press');
expect(instance.toggleEmailPasswordModal).toHaveBeenCalled();
// I ADDED THIS SECTION HERE
expect(instance.state.emailPasswordModalVisible).toBe(true);
});
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测试失败,因为instance.state.emailPasswordModalVisible = false. 这很奇怪,因为显然调用了toggleEmailPasswordModal。但是,由于我怀疑它实际上被调用了两次,因此我更新了测试,如下所示:
it('calls the toggleEmailPasswordModal method', () => {
const wrapper = shallow(<Login />);
const instance = wrapper.instance();
jest.spyOn(instance, 'toggleEmailPasswordModal');
wrapper.find(Button).first().props().onPress();
// CHANGES START HERE
// wrapper.find(Button).first().simulate('press');
// expect(instance.toggleEmailPasswordModal).toHaveBeenCalled();
expect(instance.state.emailPasswordModalVisible).toBe(true);
});
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你猜怎么了?测试正确通过。因此,显然调用wrapper.find...函数两次实际上就是调用toggleEmailPasswordModal方法两次。那么,为什么我不调用两次就检测不到呢?为什么它错误地认为该方法只被调用了一次?
我终于有了答案。根据Jest sppyOn 函数调用,我需要将instance.forceUpdate()间谍附加到组件。
it('calls the toggleEmailPasswordModal method', () => {
const wrapper = shallow(<Login />);
const instance = wrapper.instance();
const spy = jest.spyOn(instance, 'toggleEmailPasswordModal');
// This is added per https://stackoverflow.com/questions/44769404/jest-spyon-function-called/44778519#44778519
instance.forceUpdate();
wrapper.find(Button).first().props().onPress();
expect(spy).toHaveBeenCalledTimes(1);
expect(instance.state.emailPasswordModalVisible).toBe(true);
});
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现在,测试通过了!
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