ActiveMQ 消费者级别超时

Question

我试图在 Active MQ（版本 5.15.0）中创建消费者级别超时。考虑消费者选择了一条消息但无法确认，因此在这种情况下，我希望消费者超时，以便其他消费者可以选择收听经纪人的消息。

我的生产者代码在其中设置了两个消费者侦听器：

public class JmsMessageListenerAckExample {
  public static void main(String[] args) throws URISyntaxException, Exception {
    Connection connection = null;
    try {
      // Producer
      ConnectionFactory factory = createActiveMQConnectionFactory();
      connection = factory.createConnection();
      Session session = connection.createSession(false,
          Session.CLIENT_ACKNOWLEDGE);
      Queue queue = session.createQueue("customerQueue");
      String payload = "Important Task";
      Message msg = session.createTextMessage(payload);
      MessageProducer producer = session.createProducer(queue);

      System.out.println("Sending text '" + payload + "'");
      producer.send(msg);

      // Consumer
      MessageConsumer consumer1 = session.createConsumer(queue);
      consumer1.setMessageListener(
          new AckMessageListener(false, "consumer1"));
      Thread.sleep(1000);
      System.out.println("Creating new message listener to acknowledge");
      producer.send(msg);
      MessageConsumer consumer2 = session.createConsumer(queue);
      consumer2.setMessageListener(
          new AckMessageListener(true, "consumer2"));
      connection.start();

      Thread.sleep(3000);
      session.close();
    } finally {
      if (connection != null) {
        connection.close();
      }
    }
  }

  private static ActiveMQConnectionFactory createActiveMQConnectionFactory() {
    // Create a connection factory.
    final ActiveMQConnectionFactory connectionFactory =
        new ActiveMQConnectionFactory("tcp://localhost:61616");

    // Pass the username and password.
    connectionFactory.setUserName("user");
    connectionFactory.setPassword("user");
    return connectionFactory;
  }
}

这是我的消费者听众：

public class AckMessageListener implements MessageListener {
  private boolean acknowledge;
  private String consumerName;

  public AckMessageListener(boolean acknowledge, String consumerName) {
    this.acknowledge = acknowledge;
    this.consumerName = consumerName;
  }

  public void onMessage(Message message) {
    boolean terminate = !acknowledge;
    try {

      System.out.println("ConsumerName="+consumerName+", Acknowledge="+acknowledge);
      if (acknowledge) {
        try {
          message.acknowledge();
        } catch (JMSException e1) {
          e1.printStackTrace();
        }
      }

      System.out.println(message);
    } catch (InterruptedException e) {
      e.printStackTrace();
    } finally {
      if (terminate) {
        Thread.currentThread().interrupt();
      }
    }
  }
}

我想以一种consumer1侦听消息但不确认的方式进行模拟，以便它超时我正在尝试释放线程，我希望我consumer2能捡起它并确认消息，以便消息从“消息入队”中移出” 状态到“消息出队”状态，但我consumer2无法接收任何消息事件。

有什么我做错了。如何使用 Active MQ 实现消费者级别的超时？

Answer 1

处理这个问题的一种方法是使用事务（http://activemq.apache.org/how-do-transactions-work.html）。成功时调用 commit()，失败时调用 rollback()，或者如果在调用 commit() 之前关闭会话，则将发生重新传递（http://activemq.apache.org/message-redelivery-and-dlq-handling）。 html）。