在java中加载2d数组的所有值

Question

我正在尝试创建一个2D拼图滑块游戏.我创建了自己的对象gamestate来存储父游戏状态和新的游戏状态,因为我计划使用BFS解决它.示例数组看起来像

int[][] tArr = {{1,5,2},{3,4,0},{6,8,7}};

这暗示着

[1,5,2,3,4,0,6,8,7]

为了存储这个状态,我使用了以下for循环,它带来了indexOutOfBounds exceptions.

public class GameState {
public int[][] state; //state of the puzzle
public GameState parent; //parent in the game tree

public GameState() {
    //initialize state to zeros, parent to null
    state = new int[0][0];
    parent = null;
}

public GameState(int[][] state) {
    //initialize this.state to state, parent to null
    this.state = state;

    parent = null;
}

public GameState(int[][] state, GameState parent) {
    //initialize this.state to state, this.parent to parent
    this.state = new int[0][0];
    for (int i = 0; i < 3; i++){
        for (int j = 0; j < 3; j++) {
            this.state[i][j] = state[i][j];
        }
    }

    this.parent = parent;
}

有想法该怎么解决这个吗？

Answer 1

• 对于GameState()构造函数（默认构造函数）：

将其更改state = new int[0][0];为：。这样，您就可以用 (3)x(3) 个元素的容量来初始化数组。state = new int[3][3];

• 对于GameState(int[][] state, GameState parent)构造函数：

将其更改this.state = new int[0][0];为this.state = new int[state.length][state.length > 0 ? state[0].length : 0];

这样，您就可以用容量初始化数组

( state.length)x(state[0].length或0if state.lengthis 0) 元素。

另外，您必须 for 循环，直到state.lengthwithi和直到state[i].lengthwith j。

在GameState构造函数中，像这样：

public GameState(int[][] state, GameState parent) {
    //initialize this.state to state, this.parent to parent
    this.state = new int[state.length][state.length > 0 ? state[0].length : 0];
    for (int i = 0; i < state.length; i++){
        for (int j = 0; j < state[i].length; j++) {
            this.state[i][j] = state[i][j];
        }
    }

    this.parent = parent;
}

另外，作为旁注，它不是[1, 5, 2, 3, 4, 0, 6, 8, 7]，

但[[1, 5, 2], [3, 4, 0], [6, 8, 7]]。