如何gtest代码没有调用exit()

Question

我想用Google Test测试这个功能:

foo() {
    if(some_grave_error)
        exit(1);
    // do something
}

如果foo打电话,我希望我的测试失败std::exit().我该怎么做呢？它与EXPECT_EXIT的作用相反？

Answer 1

你应该foo()测试:

using fexit_callback = void(*)(int);
void foo(fexit_callback exit = &std::exit)
{
    if(some_condition)
        exit(1);
}

神奇的是,你所有的麻烦都消失了:

#include <cstdlib>
#include <cassert>

using fexit_callback = void(*)(int);
void foo(fexit_callback exit = &std::exit)
{
    if(true)
        exit(1);
}

namespace mockup
{
    int result = 0;
    void exit(int r) { result = r; }
}

int main()
{
    foo(mockup::exit);
    assert(mockup::result == 1);
}