Dhr*_*ada 2 email android cursor contactscontract
我需要通过电子邮件获取联系人信息(光标).它们必须是截然不同的 如果他收到电子邮件,每个联系人必须有一个条目.怎么做?我的目标是新的联系人API附带2.0.
1)我尝试使用CursorJoiner来做,但发生了一件奇怪的事情.这是我的代码:
MatrixCursor matCur = new MatrixCursor(
new String[]{
Contacts._ID,
Contacts.DISPLAY_NAME,
"photo_id",
"starred"
}
);
Cursor newContactCursor = managedQuery(
ContactsContract.Contacts.CONTENT_URI,
new String[]{
Contacts._ID,
Contacts.DISPLAY_NAME,
"photo_id",
"starred"
},
null,
null,
null//Contacts._ID
);
newContactCursor.moveToFirst();
Cursor emailCur = managedQuery(
ContactsContract.CommonDataKinds.Email.CONTENT_URI,
new String[] {
Email.CONTACT_ID,
Email.DATA1
},
null,
null,
Email.CONTACT_ID
);
emailCur.moveToFirst();
CursorJoiner joiner = new CursorJoiner(
newContactCursor,
new String[]{Contacts._ID},
emailCur,
new String[] {Email.CONTACT_ID}
);
for (CursorJoiner.Result joinerResult : joiner) {
switch (joinerResult) {
case LEFT:
// handle case where a row in cursorA is unique
//Log.i(TAG,"L|"+
//newContactCursor.getString(newContactCursor.getColumnIndex("_id")) );
break;
case RIGHT:
// handle case where a row in cursorB is unique
//Log.i(TAG,
//"R|"+
//emailCur.getString(emailCur.getColumnIndex("contact_id")) );
break;
case BOTH:
//Log.i(TAG,
//"L|"+
//newContactCursor.getString(newContactCursor.getColumnIndex("_id"))+
//"|R|"+
//emailCur.getString(emailCur.getColumnIndex("contact_id")) );
Log.i(TAG, newContactCursor.getString(newContactCursor.getColumnIndex("_id"))+"|"+
newContactCursor.getString(newContactCursor.getColumnIndex("display_name"))+"|"+
emailCur.getString(emailCur.getColumnIndex(Email.DATA1)));
String[] columnValues =
{newContactCursor.getString(newContactCursor.getColumnIndex("_id")),
newContactCursor.getString(newContactCursor.getColumnIndex("display_name")),
newContactCursor.getString(newContactCursor.getColumnIndex("photo_id")),
newContactCursor.getString(newContactCursor.getColumnIndex("starred"))
};
matCur.addRow(columnValues);
break;
}
}
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现在我的问题是我得到这样的输出:在这个日志中它的_id | display_name | 电子邮件ID由于隐私问题我已替换它们
1|[contact name]|[email id]
4|[contact name]|[email id]
5|[contact name]|[email id]
6|[contact name]|[email id]
7|
8|
9|
90|
91|
92|
93|
94|
95|
96|
97|
98|
99|
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但你可以看到它直接从9跳到90然后全部9 9 9,这是什么?
2)我们可以使用distinct关键字吗?是否可以使用ContactsContract等联系提供商?
尝试使用此代码段:在列表视图的同一行显示联系人姓名和电子邮件.
/**
* Populate the contact list based on account.
*/
private void populateContactList() {
// Build adapter with contact entries
Cursor cursorEmail = getContactsEmail();//get all emails
String[] fields = new String[] //fields of data to take
{ ContactsContract.Contacts._ID,
ContactsContract.Data.DISPLAY_NAME,
ContactsContract.CommonDataKinds.Email.DATA
};
SimpleCursorAdapter adapter =
new SimpleCursorAdapter(this, R.layout.contact_entry, cursorEmail ,
fields, new int[]
{R.id.UID,R.id.contactEntryText,R.id.contactEmail});
mContactList.setAdapter(adapter);
}
/**
* Obtains the contact list for the currently selected account.
*
* @return A cursor for for accessing the contact list.
*/
private Cursor getContactsEmail()
{
// Run query
Uri uri = ContactsContract.CommonDataKinds.Email.CONTENT_URI;
String[] projection = new String[] {
ContactsContract.Contacts._ID,
ContactsContract.Contacts.DISPLAY_NAME,
ContactsContract.CommonDataKinds.Email.DATA
};
String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP +"='1'";
//showing only visible contacts
String[] selectionArgs = null;
String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";
return managedQuery(uri, projection, selection, selectionArgs, sortOrder);
}
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