如何将公式作为参数传递给 r 中的函数？

Question

如何在 R 中传递公式作为参数？

下面的代码适用于前两种情况，但是当我传入公式时，出现错误： Error in model.frame.default(formula = formula, weights = weights, na.action = na.omit, : invalid type (closure) for variable '(weights)'

makeModel<-function(formula,weights) {
    m <- lm(formula, na.action = na.omit, weights = weights)
    return(m);
}
run<-function(t) {
    f<-formula(t$y~t$x+t$r)
    m <- lm(t$y~t$x+t$r, na.action = na.omit, weights = t$size)
    m <- lm(f, na.action = na.omit, weights = t$size)
    m <- makeModels(f,t$size)    
}
l<-20
x<-seq(0,1,1/l)
y<-sqrt(x)
r=round(runif(n=length(x),min=0,max=.8))
n<-1:(l+1)
size=n/sum(n)
t<-data.frame(x,y,r,n,size)
run(t)

编辑1：这段代码：

makeModel<-function(formula,weights,t) {
    print(class(weights))
    m <- lm(formula, na.action = na.omit, weights = weights,data=t)
    return(m);
}
run<-function(t) {
    f<-formula(y~x+r)
    f <- as.formula("t$y~t$x+t$r")
    m <- lm(y~x+r, na.action = na.omit, weights = t$size,data=t)
    m <- lm(f, na.action = na.omit, weights = t$size,data=t)
    m <- makeModel(f,t$size,t)    
}

产生：

model.frame.default 中的错误（公式 = 公式，数据 = t，权重 = 权重，：变量“（权重）”的类型（闭包）无效

编辑2：作品：

makeModel <- function(formula, data) {
    # size is looked in data first, which is why this works
    m <- lm(formula, na.action = na.omit, weights = size, data =  data) # works
    #m <- lm(formula, na.action = na.omit, weights = data$size, data =  data) # fails!
    return(m)
}

r 很奇怪！

有谁知道为什么以下行：weights=data$size 失败？

编辑3：得到：weights=data$size 可以工作。

makeModel<-function(formula,w,data) {
    print(class(weights))
    m <- lm(formula, na.action = na.omit, weights = size, data =  data) # works
    m <- lm(formula, na.action = na.omit, weights = data$size, data =  data) #works
    m <- lm(formula, na.action = na.omit, weights = w,data=data) # fails
    return(m);
}
run<-function(data) {
    f<-formula(y~x+r)
    #f <- as.formula("t$y~t$x+t$r")
    m <- lm(y~x+r, na.action = na.omit, weights = data$size,data=data)
    m <- lm(f, na.action = na.omit, weights = data$size,data=data)
    m <- makeModel(f,data$size,data)    
}

最后一个失败并显示： eval(extras, data, env) 中的错误：找不到对象“w”

Answer 1

请参阅 中的示例?as.formula。您不应该从变量名称中显式调用变量。该公式应该是一个抽象的，并且lm知道要从中提取哪些变量data，您应该指定哪些变量。

makeModels <- function(formula, data) {
  # size is looked in data first, which is why this works
  m <- lm(formula, na.action = na.omit, weights = size, data =  data)
  return(m)
}

run <- function(t) {
  f <- formula(y ~ x + r)
  m1 <- lm(formula = f, na.action = na.omit, weights = size, data = t)
  m2 <- makeModels(formula = f, data = t)
  return(list(m1, m2))
}

l<-20
x<-seq(0,1,1/l)
y<-sqrt(x)
r=round(runif(n = length(x), min = 0, max = 0.8))
n<-1:(l+1)
size=n/sum(n)
t<-data.frame(x,y,r,n,size)
run(t)

[[1]]

Call:
lm(formula = f, data = t, weights = t$size, na.action = na.omit)

Coefficients:
(Intercept)            x            r  
   0.327154     0.706553    -0.008167  


[[2]]

Call:
lm(formula = formula, data = data, weights = size, na.action = na.omit)

Coefficients:
(Intercept)            x            r  
   0.327154     0.706553    -0.008167