导出动态变量

Dev*_*wal 0 node.js promise node-modules

我正在尝试在node.js中导出一个变量,如下所示:

let news = [];

const fetchNews = new Promise ((resolve, reject) => {

  let query = 'SELECT id, name FROM news';

  mysql.query(query, [], (error, results) => {

    if (error)
      reject({error: `DB Error: ${error.code} (${error.sqlState})`})

    results = JSON.parse(JSON.stringify(results));

    news = results;

    resolve(results);

  });

});

if(!news.length)
  fetchNews
    .then(results => {news = results})
    .catch(err => {console.log('Unable to fetch news', err)});

exports.news = news;
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当我在其他模块中使用此代码时,如下所示:

const news = require('./news.js').news;

console.log(news);
//returns [];
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有人可以在第一段代码中指出我的错误吗?

Akr*_*ion 6

你做这件事的方式有几个看起来很奇怪:

您有一个异步操作,但您只想要该值而不实际等待操作完成.尝试这样的事情:

module.exports = new Promise ((resolve, reject) => {
  mysql.query('SELECT id, name FROM news', (error, results) => {
    if (error)
      reject({error: `DB Error: ${error.code} (${error.sqlState})`})

    resolve(JSON.parse(JSON.stringify(results)));
  });
});
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然后得到消息:

var getNewsAsync = require('./news')
getNewsAsync.then(news => console.log(news))
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如果您实际使用mysqllib的async/await,它会更干净/更短.

更新:

随着节点8及以上,你应该能够promisifymySQLLIB方法.虽然可能有更好的npm选项可以让它工作.这是一个未经测试的版本:

const mysql = require('mysql');
const util = require('util');
const conn = mysql.createConnection({yourHOST/USER/PW/DB});
const query = util.promisify(conn.query).bind(conn);

module.exports = async () => {
  try {return await query('SELECT id, name FROM news')} finally {conn.end()}
}
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得到消息:

var getNewsAsync = require('./news')
console.log(await getNewsAsync())
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