如何使用Python将许多文件上传到云文件？

Question

我正在使用cloudfile模块将文件上传到rackspace云文件,使用类似这样的伪代码:

import cloudfiles

username = '---'
api_key = '---'

conn = cloudfiles.get_connection(username, api_key)
testcontainer = conn.create_container('test')

for f in get_filenames():
    obj = testcontainer.create_object(f)
    obj.load_from_filename(f)

我的问题是我要上传很多小文件,这种方式需要太长时间.

埋藏在文档中,我看到有一个类ConnectionPool,据说可以用来并行上传文件.

有人可以说明我如何让这段代码一次上传多个文件？

Answer 1

该ConnectionPool班是用于那些ocasionally有送东西给Rackspace的多线程应用程序.

这样您就可以重用连接,但如果您有100个线程,则不必保持100个连接打开.

您只是在寻找多线程/多处理上传器.以下是使用该multiprocessing库的示例:

import cloudfiles
import multiprocessing

USERNAME = '---'
API_KEY = '---'


def get_container():
    conn = cloudfiles.get_connection(USERNAME, API_KEY)
    testcontainer = conn.create_container('test')
    return testcontainer

def uploader(filenames):
    '''Worker process to upload the given files'''
    container = get_container()

    # Keep going till you reach STOP
    for filename in iter(filenames.get, 'STOP'):
        # Create the object and upload
        obj = container.create_object(filename)
        obj.load_from_filename(filename)

def main():
    NUMBER_OF_PROCESSES = 16

    # Add your filenames to this queue
    filenames = multiprocessing.Queue()

    # Start worker processes
    for i in range(NUMBER_OF_PROCESSES):
        multiprocessing.Process(target=uploader, args=(filenames,)).start()

    # You can keep adding tasks until you add STOP
    filenames.put('some filename')

    # Stop all child processes
    for i in range(NUMBER_OF_PROCESSES):
        filenames.put('STOP')

if __name__ == '__main__':
    multiprocessing.freeze_support()
    main()