Ast*_*rid 4 python multi-index dataframe pandas
这是我想要做的一个例子:
import io
import pandas as pd
data = io.StringIO('''Fruit,Color,Count,Price
Apple,Red,3,$1.29
Apple,Green,9,$0.99
Pear,Red,25,$2.59
Pear,Green,26,$2.79
Lime,Green,99,$0.39
''')
df_unindexed = pd.read_csv(data)
df = df_unindexed.set_index(['Fruit', 'Color'])
Run Code Online (Sandbox Code Playgroud)
输出:
Out[5]:
Count Price
Fruit Color
Apple Red 3 $1.29
Green 9 $0.99
Pear Red 25 $2.59
Green 26 $2.79
Lime Green 99 $0.39
Run Code Online (Sandbox Code Playgroud)
现在假设我想计算"颜色"级别中的键数:
L = []
for i in pd.unique(df.index.get_level_values(0)):
L.append(range(df.xs(i).shape[0]))
list(np.concatenate(L))
Run Code Online (Sandbox Code Playgroud)
然后我将结果列表添加[0,1,0,1,0]为新列:
df['Bob'] = list(np.concatenate(L))
Run Code Online (Sandbox Code Playgroud)
如此:
Count Price Bob
Fruit Color
Apple Red 3 $1.29 0
Green 9 $0.99 1
Pear Red 25 $2.59 0
Green 26 $2.79 1
Lime Green 99 $0.39 0
Run Code Online (Sandbox Code Playgroud)
我的问题:
如何使Bob列成为与同一级别Color的索引?这就是我要的:
Count Price
Fruit Color Bob
Apple Red 0 3 $1.29
Green 1 9 $0.99
Pear Red 0 25 $2.59
Green 1 26 $2.79
Lime Green 0 99 $0.39
Run Code Online (Sandbox Code Playgroud)
你在找cumcount?如果是这样,您可以放弃循环并矢量化您的解决方案.
df = df.set_index(df.groupby(level=0).cumcount(), append=True)
print(df)
Count Price
Fruit Color
Apple Red 0 3 $1.29
Green 1 9 $0.99
Pear Red 0 25 $2.59
Green 1 26 $2.79
Lime Green 0 99 $0.39
Run Code Online (Sandbox Code Playgroud)
或者,如果你喜欢一下子做这件事,
df_unindexed = pd.read_csv(data)
df = df_unindexed.set_index(['Fruit', 'Color', df.groupby('Fruit').cumcount()])
print(df)
Count Price
Fruit Color
Apple Green 0 9 $0.99
Red 1 3 $1.29
Lime Green 0 99 $0.39
Pear Green 1 26 $2.79
Red 0 25 $2.59
Run Code Online (Sandbox Code Playgroud)
要重命名索引,请使用rename_axis:
df = df.rename_axis(['Fruit', 'Color', 'Bob'])
print(df)
Count Price
Fruit Color Bob
Apple Red 0 3 $1.29
Green 1 9 $0.99
Pear Red 0 25 $2.59
Green 1 26 $2.79
Lime Green 0 99 $0.39
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
156 次 |
| 最近记录: |