我遇到了将星期几字符串转换为time.Weekday值的问题。我找不到time包中内置的任何东西。
然后我编写了这个简单的函数(满足了我的需求):
var daysOfWeek = [...]string{
"Sunday",
"Monday",
"Tuesday",
"Wednesday",
"Thursday",
"Friday",
"Saturday",
}
func parseWeekday(v string) (time.Weekday, error) {
for i := range daysOfWeek {
if daysOfWeek[i] == v {
return time.Weekday(i), nil
}
}
return time.Sunday, fmt.Errorf("invalid weekday '%s'", v)
}
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在 Golang 中是否有其他推荐或更惯用的方法来执行此转换?
谢谢!
前言:我在 中发布了此实用程序github.com/icza/gox,请参阅timex.ParseWeekday()。
是的,使用映射而不是数组,这样查找会更快更直接:
var daysOfWeek = map[string]time.Weekday{
"Sunday": time.Sunday,
"Monday": time.Monday,
"Tuesday": time.Tuesday,
"Wednesday": time.Wednesday,
"Thursday": time.Thursday,
"Friday": time.Friday,
"Saturday": time.Saturday,
}
func parseWeekday(v string) (time.Weekday, error) {
if d, ok := daysOfWeek[v]; ok {
return d, nil
}
return time.Sunday, fmt.Errorf("invalid weekday '%s'", v)
}
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测试它:
fmt.Println(parseWeekday("Monday"))
fmt.Println(parseWeekday("Friday"))
fmt.Println(parseWeekday("invalid"))
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输出(在Go Playgorund上试试):
Monday <nil>
Friday <nil>
Sunday invalid weekday 'invalid'
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提示:
您甚至可以使用for循环来安全地初始化daysOfWeek地图,如下所示:
var daysOfWeek = map[string]time.Weekday{}
func init() {
for d := time.Sunday; d <= time.Saturday; d++ {
daysOfWeek[d.String()] = d
}
}
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测试和输出是一样的。在Go Playground上试试这个。
此映射解决方案的另一个不错的特性(与您的数组解决方案相比)是您可以在同一个映射中列出额外的有效值,这些值可以在time.Weekday没有额外解析代码的情况下被解析。
例如,让我们还将 3 个字母的短工作日名称解析为它们的time.Weekday等效名称,例如"Mon"to time.Monday。
这个扩展可以通过一个简单的循环添加:
var daysOfWeek = map[string]time.Weekday{}
func init() {
for d := time.Sunday; d <= time.Saturday; d++ {
name := d.String()
daysOfWeek[name] = d
daysOfWeek[name[:3]] = d
}
}
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测试它:
fmt.Println(parseWeekday("Monday"))
fmt.Println(parseWeekday("Friday"))
fmt.Println(parseWeekday("Mon"))
fmt.Println(parseWeekday("Fri"))
fmt.Println(parseWeekday("invalid"))
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输出(在Go Playground上试试):
Monday <nil>
Friday <nil>
Monday <nil>
Friday <nil>
Sunday invalid weekday 'invalid'
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请参阅类似问题:从字符串中获取整数月份值
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