Java更优雅的方式用if语句写if语句

Question

是否有更优雅/更短/有组织的方式来编写这段代码？

for (int i = 0; i < SCREENSIZE; i++) {
        for (int j = 0; j < SCREENSIZE; j++) {
            if (map[y + i][x + j] == '@')
                g.drawImage(item, j * TILESIZE,i * TILESIZE, null);
            else if (map[y + i][x + j] == ' ')
                g.drawImage(ground, j * TILESIZE,i * TILESIZE, null);
            else if (map[y + i][x + j] == 'i')
                g.drawImage(bush, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == '~')
                g.drawImage(ocean, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == '=')
                g.drawImage(fence, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == '#')
                g.drawImage(grass, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == 'Y')
                g.drawImage(townsPerson, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == '/')
                g.drawImage(house01, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == '¯')
                g.drawImage(house02, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == '\\')
                g.drawImage(house03, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == '[')
                g.drawImage(house04, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == 'n')
                g.drawImage(house05, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == '_')
                g.drawImage(house06, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == ']')
                g.drawImage(house07, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == '`')
                g.drawImage(cground, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == 'O')
                g.drawImage(boulder, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == 'Ÿ')
                g.drawImage(alien, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == '.')
                g.drawImage(tree01, j * TILESIZE, i * TILESIZE, null);
            else if (map[y + i][x + j] == 'T')
                g.drawImage(tree02, j * TILESIZE, i * TILESIZE, null);
        }
    }

Answer 1

第一个改进可能是使用开关/案例结构,但在你的情况下,一个简单的map(Map<Char,Image>)会更好.

更进一步,您可以使用枚举而不是字符来识别对象,这将帮助您避免打字错误,但至少您应该使用字符常量,如

public static final char MAP_ITEM = '@';
public static final char MAP_GROUND = ' ';

等等.