如何在 GraphQL 中执行突变?

Lan*_*eyo 6 node.js graphql

在 GraphQL 中,我们基本上有两种类型的操作:查询和突变。虽然文档中对查询进行了很好的描述,并且有很多示例,但我很难理解如何执行突变。突变显然是更新方法。

我创建了非常简单的 Node.js 服务器:

var express = require("express");
var graphqlHTTP = require("express-graphql");
var graphql = require("graphql");
var inMemoryDatabase = require("./inMemoryDatabase").inMemoryDatabase;
var _ = require("lodash-node");

var userType = new graphql.GraphQLObjectType({
  name: "User",
  fields: {
    id: { type: graphql.GraphQLString },
    name: { type: graphql.GraphQLString }
  }
});

var queryType = new graphql.GraphQLObjectType({
  name: "Query",
  fields: {
    user: {
      type: userType,
      args: {
        id: { type: graphql.GraphQLString }
      },
      resolve: function(parent, { id }) {
        return _.find(inMemoryDatabase, { id: id });
      }
    }
  }
});

var mutationType = new graphql.GraphQLObjectType({
  name: "Mutation",
  fields: {
    user: {
      type: userType,
      args: {
        id: { type: graphql.GraphQLString },
        name: { type: graphql.GraphQLString }
      },
      resolve: function(parent, { id, name }) {
        var index = _.findIndex(inMemoryDatabase, { id: id });
        inMemoryDatabase.splice(index, 1, { id: id, name: name });
        return _.find(inMemoryDatabase, { id: id });
      }
    }
  }
});

var schema = new graphql.GraphQLSchema({
  query: queryType,
  mutation: mutationType
});

var app = express();
app.use(
  "/graphql",
  graphqlHTTP({
    schema: schema,
    graphiql: true
  })
);

var port = 9000;
if (process.env.PORT) {
  port = process.env.PORT;
}

app.listen(port);
console.log("Running a GraphQL API server at localhost:" + port + "/graphql");
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内存数据库只是在 User 对象的数组中{id, name}

var inMemoryDatabase = [
  {
    id: "31ce0260-2c23-4be5-ab78-4a5d1603cbc8",
    name: "Mark"
  },
  {
    id: "2fb6fd09-2697-43e2-9404-68c2f1ffbf1b",
    name: "Bill"
  }
];

module.exports = {
  inMemoryDatabase
};
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执行查询以通过 id 获取用户如下所示:

{
 user(id: "31ce0260-2c23-4be5-ab78-4a5d1603cbc8"){
  name
 }
}
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突变改变用户名会是什么样子?

Lan*_*eyo 1

@Austio 的答案非常接近,但正确的方法是:

mutation updateUser {
  user(id: "31ce0260-2c23-4be5-ab78-4a5d1603cbc8", name: "Markus") {
    id
    name
  }
}
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