赛马计划,功能调用被忽略

Question

打印出代码时,它会运行,但似乎不运行该coinflip()功能.目前只试图打印出第一匹马串,随机前进.

#include <iostream>
#include <string>
#include <time.h>
#include <stdlib.h>
using namespace std;

string h0 = "0................";
string h1 = "1................";
string h2 = "2................";
string h3 = "3................";
string h4 = "4................";
int position0 = 0;
string coinflip0(string h0);

int main(){

   cout << "Press Enter to begin! " <<endl;
   cin.ignore();
   std::cout << h0 << endl; //print string
   cout << h1 << endl;
   cout << h2 << endl;
   cout << h3 << endl;
   cout << h4 << endl;

//      srand(time(NULL));//time goes back to zero for each loop

   while(h0.at(16) != 0) {
        cout << "\n Press Enter to continue " << endl;
        cin.ignore();

        string coinflip0(h0); // call function
        cout << h0 << endl; //print new string
   } //end while
} // end main

string coinflip0(string h0) {

   // find random number(0 or 1)
   int num = rand() % 2;
        cout << num << endl;
   position0 = position0 + num;

   if(num==1){
        std::swap(h0[position0], h0[position0+1]);
   } // end if

   return h0;
}//end coin flip

输出:

Press Enter to begin!

0................
1................
2................
3................
4................

 Press Enter to continue

0................

 Press Enter to continue

0................

 Press Enter to continue

0................

 Press Enter to continue

Answer 1

string coinflip0(h0); // call function

这实际上不是函数调用.这是一个变量声明,类似于:

string coinflip0 = h0;

要打电话给这个功能string.一个简单的方法coinflip0(h0)就可以了.我认为你想把结果分配回去h0,所以也是这样做的:

h0 = coinflip0(h0);