将变量从href传递到另一个php页面

zer*_*rey 3 php mysql

我有这个代码:

<a id="various3" href="picture.php?id=',$pid,'" title="'.$info.'"><img src="picture.php?id=',$pid,'" width="150" height="210"></a>
Run Code Online (Sandbox Code Playgroud)

它将id传递给我的picture.php,我在查询字符串上使用它.

$sql = sprintf("select pics, ext from `06-07` where id='%d'",$_GET['id']);
Run Code Online (Sandbox Code Playgroud)

是否可以使用此方法传递多个变量?因为我想把"dept"和"id"一起传递.如果是的话怎么样?

我试过这个:

<a id="various3" href="picture.php?id=',$pid,'&dept=',$dept,'" title="'.$info.'"><img src="picture.php?id=',$pid,'&dept=',$dept,'" width="150" height="210"></a> 
Run Code Online (Sandbox Code Playgroud)

与匹配

$sql = sprintf("select pics, ext from 06-07 where id='%d' AND dept='%s'", $_GET['id'], $_GET['dept']); but it doen't work. what's wrong?
Run Code Online (Sandbox Code Playgroud)

小智 9

<a href="test.php?page_name=<?php echo $this_month; ?>">
Run Code Online (Sandbox Code Playgroud)

通过get方法在另一个页面上访问它:

$file_name = $_GET['page_name'];
Run Code Online (Sandbox Code Playgroud)