使用表达式为实体框架构建 Array.Contains

Kel*_*ine 3 c# expression-trees

我想在Where-Contains 和Select 中都有一个变量字段。“field_a”是我想要变量的人(有时我想要 field_b 或 _c;它们是字符串)。下面的代码正确构建了 Select as Select(x => x.field_a)。如何让Where子句的第二部分说,&& targetCodes.Contains(x.field_a)?[db是一个DbContext,itemsArray是具有名为 的字符串属性的对象数组Code。]

    using (var db = dbFactory.CreateInstance())
    {
        var parameter = Expression.Parameter(typeof(myTable), "x");
        var field = Expression.Property(parameter, "field_a");
        var selector = Expression.Lambda(field, parameter);
        var targetCodes = itemsArray.Select(i => i.Code).ToArray();
        var query = db.myTables
            .Where(x => x.companyId == 1 && targetCodes.Contains(x.field_a))
            .Select((Expression<Func<myTable, string>>)selector);
        return await query.ToArrayAsync();
    }
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Ňuf*_*Ňuf 5

也许最困难的部分是找到MethodInfo方法.Contains()。您可以使用typeof(IEnumerable<string>).GetMethod(...).Where(...),但对于具有多个重载的泛型方法来说通常很难做到正确。这是一个小技巧,它使用 C# 编译器通过创建临时表达式来找到正确的重载:

Expression<Func<IEnumerable<string>, bool>> containsExpr = (IEnumerable<string> q) => q.Contains((string)null);
var containsMethod = (containsExpr.Body as MethodCallExpression).Method;
// containsMethod should resolve to this overload:
// System.Linq.Enumerable.Contains<string>(IEnumerable<string>, string)
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程序的其余部分只是通过调用适当的Expression.XYZ()方法来构建表达式:

var companyIdEquals1 = Expression.Equal(
    Expression.Property(parameter, nameof(myTable.companyId)),
    Expression.Constant(1));

var targetCodesContains = Expression.Call(
    containsMethod,
    Expression.Constant(targetCodes),
    field/*reuses expression you already have*/);

var andExpr = Expression.And(companyIdEquals1, targetCodesContains);
var whereExpr = (Expression<Func<myTable, bool>>)Expression.Lambda(andExpr, parameter);

var query = db//.myTables
    .Where(whereExpr)
    .Select((Expression<Func<myTable, string>>)selector);
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