与隔离的双向通信在Dart 2中

Question

我正在尝试隔离，而我想知道如何让其中的一些人进行繁重的计算，当根隔离询问他们当前的计算值时，他们会“按需”响应。

据我所知，可以用作新创建的隔离的消息的唯一对象是SendPort，这意味着只有生成的隔离可以与根隔离进行通信。我尝试发送<SendPort，ReceivePort>元组，但是由于ReceivePort不是SendPort，因此被认为是非法的。

简而言之：

根<-隔离良好

根<->隔离如何？

Answer 1

随着Gunter的评论，我做了这个：

import 'dart:async';
import 'dart:io';
import 'dart:isolate';

Stopwatch stopwatch = new Stopwatch();

main(args) async {
  ReceivePort rPort = new ReceivePort();
  rPort.listen((data) {
    print("<root> $data received");
    if (data is List) {
      String action = data[0];
      if (action == "register") {
        (data[1] as SendPort).send(stopwatch.elapsedMilliseconds);
      }
    }
  });
  stopwatch.start();
  await Isolate.spawn(elIsolate, rPort.sendPort);
  print("isolate spawned in ${stopwatch.elapsedMilliseconds} msecs"); //isolate spawned in 377 msecs
}

void elIsolate(SendPort sPort) {
  ReceivePort rPort = new ReceivePort();
  rPort.listen((data) {
    print("<Isolate> '$data' received"); //<Isolate> '387' received
  });
  sPort.send(["register", rPort.sendPort]);
}

虽然使用Kevin的答案，但代码简化为：

import 'dart:async';
import 'dart:io';
import 'dart:isolate';
import 'package:stream_channel/stream_channel.dart';

Stopwatch stopwatch = new Stopwatch();

main(args) async {
  ReceivePort rPort = new ReceivePort();
  IsolateChannel channel = new IsolateChannel.connectReceive(rPort);
  channel.stream.listen((data) {
    print("<root> '$data' received at ${stopwatch.elapsedMilliseconds} msecs"); //<root> 'hello world' received at 1141 msecs
    channel.sink.add(stopwatch.elapsedMilliseconds);
  });
  stopwatch.start();
  await Isolate.spawn(elIsolate, rPort.sendPort);
  print("isolate spawned in ${stopwatch.elapsedMilliseconds} msecs"); //isolate spawned in 1111 msecs
}

void elIsolate(SendPort sPort) {
  IsolateChannel channel = new IsolateChannel.connectSend(sPort);
  channel.stream.listen((data) {
    print("<Isolate> '$data' received");
  });
  channel.sink.add("hello world");
}

Answer 2

看IsolateChannel从包：stream_channel。

这应该为您尝试做的事情提供很多帮助。