查找RotatedRect的宽度和高度

Question

请参阅此C ++代码，我尝试在python中进行更改以执行完全相同的操作，但我陷入for循环中以找到Aspect_ratio。我没有得到任何线索，以获得最小和最大 宽度和高度的RotatedRect在python作为替代品RotatedRect的C ++中Python是cv2.boxPoints

import cv2
from matplotlib import pyplot as plt
img = cv2.imread('C:/Users/Zeeesh/Desktop/1.jpg', cv2.IMREAD_GRAYSCALE)
ret,thresh = cv2.threshold(img,200,255,0)
img1,contours, hierarchy = cv2.findContours(thresh,cv2.RETR_TREE,cv2.CHAIN_APPROX_NONE)
out = cv2.cvtColor(img, cv2.COLOR_GRAY2BGR)
for contour in contours:
    rect = cv2.minAreaRect(contour)
    (x, y), (width, height), angle = rect
    aspect_ratio = min(width, height) / max(width, height)

    thresh1 = 0.2
    if (aspect_ratio > thresh1):
        print('Straight Line')
        for pt in contour:
            cv2.drawContours(out, [pt], 0,255,0)
    else:
        print('Curve')
        for pt in contour:
            cv2.drawContours(out, [pt], 0,0,255)






plt.imshow(out)

Answer 1

您可以找到width和height的旋转矩形：

rect = cv2.minAreaRect(contour)
(x, y), (width, height), angle = rect

那么长宽比是：

aspect_ratio = min(width, height) / max(width, height)