Python：只接受特定的IP（套接字）

Question

我有一个由 java 客户端和 python 服务器组成的程序。python 服务器可以接收多个连接，客户端将每 17 秒尝试连接到服务器一次。我的问题：服务器应该只接受与用户之前输入的 IP 的一个连接。

HOST = '0.0.0.0'
PORT = 1979

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print 'Socket created!'

try:
        s.bind((HOST, PORT))
except socket.error as e:
    print(e)
        sys.exit()

print 'Socket bind complete'

s.settimeout(30)
s.listen(10)

print 'Listening...'

timeout = 8

timeout_start = time.time()

while time.time() < timeout_start + timeout:
    try:
            conn, addr = s.accept()
        msg = conn.recv(1024)
        print ('--------------------------------------')
        print (msg) 
    except socket.timeout as e:
        print(e,': No client out there :(')
        s.close()
        break

        print 'Client connected: ' + addr[0] + ':' + str(addr[1])
    print ('--------------------------------------')

s.close()   

该套接字接受所有传入连接。我想在套接字之前添加以下内容：

connectip = raw_input('Please enter the IP of the client you want to connect to ')

然后套接字应该只接受具有用户在“connectip”中指定的IP的客户端。

请原谅我糟糕的英语

Answer 1

您仍然必须接受它，但可以在传输任何数据之前将其关闭。

connectip = raw_input("Please enter the IP of the client you want to connect to ")
conn, addr = s.accept()
if addr[0] != connectip:
    conn.shutdown(SHUT_RDWR)
    conn.close()
else:
    # do what ever you want here

顺便说一句，您确实应该切换到 python 3，因为 python 2 很快就会被弃用。