我一直在使用PHP一段时间,但不得不转向ASP.NET MVC
我想获得像下面这样的数组
Order[0]
=>MaterialName="MName"
=>MaterialType=1
=>MaterialDescription="Description"
=>Roles[0]
=>"Televsion"= "ABCTV"
=>"Radio"= "ABC Radio"
=>Roles[1]
=>"Televsion"= "DEFTV"
=>"Radio"= "DEF Radio"
Order[1]
=>MaterialName="MName"
=>MaterialType=1
=>MaterialDescription="Description"
=>Roles[0]
=>"Televsion"= "ABCTV"
=>"Radio"= "ABC Radio"
=>Roles[1]
=>"Televsion"= "DEFTV"
=>"Radio"= "DEF Radio"
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我可以通过制作第一个数组并在之后追加其他数据来在PHP中生成这个.
并循环以获取其中的值.
我希望在ASP.NET MVC中完成此操作,但无济于事.
数组不允许附加名称和字典.
首先,你需要一个模型.
在你的情况下,它看起来像这样
public class Order
{
public string MaterialName { get; set; }
public int MaterialType { get; set; } // consider making this an Enum
public string MaterialDescription { get; set; }
public Dictionary<string, string> Roles { get; set; }
}
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现在,您可以定义您的集合:
var orders = new System.Collections.Generic.List<Order>{
new Order
{
MaterialName = "MName",
MaterialType = 1,
MaterialDescription = "Description",
Roles = new Dictionary<string, string>
{
{"Television", "ABCTV"},
{"Radio", "ABCDEF RadioTV"},
}
},
new Order
{
MaterialName = "MName",
MaterialType = 1,
MaterialDescription = "Description",
Roles = new Dictionary<string, string>
{
{"Television", "ABCTV"},
{"Radio", "ABCDEF RadioTV"},
}
}
};
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编辑:也可能是你Roles是一个Dictionary数组,在这种情况下我们可以这样做:
public class Order
{
public string MaterialName { get; set; }
public int MaterialType { get; set; } // consider making this an Enum
public string MaterialDescription { get; set; }
public List<Dictionary<string, string>> Roles { get; set; }
}
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现在,您可以定义您的集合:
var orders = new System.Collections.Generic.List<Order>{
new Order
{
MaterialName = "MName",
MaterialType = 1,
MaterialDescription = "Description",
Roles = new List<Dictionary<string, string>> {
new Dictionary<string, string>
{
{"Television", "ABCTV"},
{"Radio", "ABCDEF RadioTV"},
},
new Dictionary<string, string>
{
{"Television", "ABCTV"},
{"Radio", "ABCDEF RadioTV"},
}
},
new Order
{
MaterialName = "MName",
MaterialType = 1,
MaterialDescription = "Description",
Roles = new List<Dictionary<string, string>> {
new Dictionary<string, string>
{
{"Television", "ABCTV"},
{"Radio", "ABCDEF RadioTV"},
},
new Dictionary<string, string>
{
{"Television", "ABCTV"},
{"Radio", "ABCDEF RadioTV"},
}
},
};
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