C++浮点数和字节数组的问题

Phi*_*len 3 c++ avr unions

我正在研究arduino(基于AVR平台),我有一个接收浮点数并将其写入EEPROM的方法.我必须将float转换为字节数组以与EEPROM交互.我有两个功能如下:

void WriteFloatToEEPROM(int address, float value) {
    union {
        byte byteVal[4];
        float floatVal;
    } data;

    data.floatVal = value;

    for (int i = 0; i < 4; i++) {
        EEPROM.update(address + i, data.byteVal[i]);
    }   
}

float ReadFloatFromEEPROM(int address) {
    union {
        byte byteVal[4];
        float floatVal;
    } data;

    for (int i = 0; i < 4; i++) {
        uint8_t readValue = EEPROM.read(address + i);

        data.byteVal[i] = readValue;        
    }

    return data.floatVal;
}
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当我打印出结果时,我得到以下几个例子:

Read value at address 50 for float read 0
Read value at address 51 for float read 0
Read value at address 52 for float read 0
Read value at address 53 for float read 0
    Returned float val for address 50:0.00
Read value at address 90 for float read 0
Read value at address 91 for float read 0
Read value at address 92 for float read 0
Read value at address 93 for float read 160
    Returned float val for address 90:-0.00
Read value at address 130 for float read 44
Read value at address 131 for float read 113
Read value at address 132 for float read 61
Read value at address 133 for float read 138
    Returned float val for address 130:-0.00
Read value at address 170 for float read 0
Read value at address 171 for float read 0
Read value at address 172 for float read 0
Read value at address 173 for float read 0
    Returned float val for address 170:0.00
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我使用工会错误/向后写入EEPROM还是什么?如果有人有更好的方法,我愿意接受建议.提前致谢

Jar*_*d42 7

读取不是联合的"活动"字段是UB(未定义行为).

你必须使用memcpy:

void WriteFloatToEEPROM(int address, float value) {
    byte byteVal[sizeof(float)];
    memcpy(byteVal, &value, sizeof(float));

    for (int i = 0; i < sizeof(float); i++) {
        EEPROM.update(address + i, byteVal[i]);
    }   
}

float ReadFloatFromEEPROM(int address) {
    byte byteVal[sizeof(float)];

    for (int i = 0; i < sizeof(float); i++) {
        byteVal[i] = EEPROM.read(address + i);
    }

    float f;
    memcpy(&f, byteVal, sizeof(float));
    return f;
}
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  • @KillzoneKid我想我知道你要去哪里.你说我们可以安全地将`float*`转换为`char*`,所以完全杀掉中间缓冲区并直接读入`float`.循环`float_as_charp [i] = read(i);`.我想不出一个很好的理由,为什么那不起作用. (2认同)