Kar*_*n93 4 sql t-sql sql-server algorithm
我需要以Group By特定的方式找到一些方法来获取某些数据.
id Number FROM TO
1 240 201710 201712
1 240 201712 201801
1 240 201801 201803
1 300 201803 201805
1 240 201805 999999
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我需要他们以这种方式分组:
id TEXT
1 201710 - 201803: 240, 201803 - 20180: 300, 201805 - 999999: 240
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我的问题是获得正确的分组.它具有组行1-3和设置FROM来201710和TO到201803.但我不能按数字分组,因为它可以在以后再改变.
有任何想法吗?
我唯一的想法是检查下一行的FROM with FROM,如果数字匹配则将其设置为前一个FROM.然后,我可以通过组id, number和FROM,走MAX的TO.但我真的不想使用光标.
这里有一个测试文件:
DECLARE @Test AS table
(
customerid int,
Number int,
DateFrom int,
DateTo int
);
INSERT INTO @Test
VALUES (1, 240, 201710, 201712),
(1, 240, 201712, 201801),
(1, 240, 201801, 201803),
(1, 300, 201803, 201805),
(1, 240, 201805, 999999);
SELECT t.customerid,
t.Number,
t.DateFrom,
t.DateTo
FROM @Test t;
SELECT customerid,
STUFF(
(SELECT DISTINCT
', ' + CONVERT(varchar(100), (t2.DateFrom)) + ' - ' + CONVERT(varchar(100), (t2.DateTo)) + ' : '
+ CONVERT(varchar(100), (t2.Number))
FROM @Test t2
FOR XML PATH('')),
1,
2,
'') AS Text
FROM @Test t
WHERE t.customerid = t2.customerid
GROUP BY t.customerid;
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试试这个:
;WITH cte AS (
SELECT t.customerid,
t.Number,
t.DateFrom,
t.DateTo,
ROW_NUMBER() over (order by datefrom) - ROW_NUMBER() over (partition by number order by datefrom) grpCol
FROM @Test t
), cte2 AS (
SELECT customerid,
cast(MIN(datefrom) as varchar(10)) + ' - ' + cast(MAX(dateto) as varchar(10)) + ': ' + cast(number as varchar(10)) [text],
MIN(datefrom) datefrom
FROM cte c
group by customerid, number, grpCol
)
SELECT customerid,
(select [text] + ', ' from cte2 where customerid = c.customerid order by datefrom for xml path('')) [text]
FROM cte2 c
GROUP BY customerid
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输出:
customerid | text
1 | 201710 - 201803: 240, 201803 - 201805: 300, 201805 - 999999: 240,
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