aic*_*pom 4 hibernate nullpointerexception composite-primary-key
我正在获取 Hibernate @EmbeddedId 的问题。我的@EmbeddedId的代码是:
@Embeddable
public class EnrolRegEmbededId implements Serializable
{
@Column(name="ENROL_NO")
private String enrolNo;
@Column(name="REG_NO")
private String regNo;
}
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我的实体类是:
@Entity
@Table(name = "PTAX_ENROL_REG_PRINCIPAL_INFO")
public class Enrol_reg_principal_info implements Serializable {
@EmbeddedId
private EnrolRegEmbededId enrolReg;
@Column(name = "APPLN_TYPE")
private String type;
@Column(name = "FIRST_NM")
private String f_name;
@Column(name = "MIDDLE_NM")
private String m_name;
@Column(name = "LAST_NM")
}
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问题是:当 enrolNo 和 regNo 都有值时,我从“Enrol_reg_principal_info”类获取数据。但当 enrolNo 或 regNo 有值时,会出现 NUllPointerException。
hql 是: String hql = " from Enrol_reg_principal_info prin where prin.enrolReg.regNo=:id"; 用于获取 regNo 的值。
String hql = " from Enrol_reg_principal_info prin where prin.enrolReg.enrolNo=:ec"; 用于获取 enrolNO 的值。
方法是:
public EnrolRegPrinModel masterDetailsEC(String EC) throws Exception {
EnrolRegPrinModel ecDetails = new EnrolRegPrinModel();
Enrol_reg_principal_info info = new Enrol_reg_principal_info();
Session s = null;
try {
s = sessionFactory.openSession();
String hql = " from Enrol_reg_principal_info prin where
prin.enrolReg.enrolNo=:ec";
Query q = s.createQuery(hql);
q.setString("ec", EC);
info = (Enrol_reg_principal_info) q.uniqueResult();
} catch (Exception ex) {
ex.printStackTrace();
} finally {
s.close();
}
return ecDetails;
}
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请帮忙。提前致谢
当您说 时EmbeddedId,它表示一个复合主键,它需要一个非空且唯一的值。JPA 期望这些列不为空并且是唯一的。据此选择您的列。
另外,我不确定您是否已经有了 getter 和 setter。嵌入的 id 类需要正确equals()设置hashcode()方法。
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