运行总计 - 日期差异

Question

这就是表格的样子:

create table IncomeTest (SubjectId int, Date_Value date, debit number, credit number);

insert into IncomeTest values (1, '7-SEP-2017', 11000, 0);
insert into IncomeTest values (1, '7-DEC-2017', 6000, 0);
insert into IncomeTest values (1, '9-JAN-2018', 0, 16110);
insert into IncomeTest values (1, '9-JUL-2018', 0, 619.6);
insert into IncomeTest values (1, '23-JUL-2018', 0, 270.4);

commit;

借方代表现金,贷方代表现金.插入表后,您将获得以下数据:

SubjectID | Date_value | Debit |  Credit 
    1       9/7/2017     11000         0
    1       12/7/2017     6000         0
    1       1/9/2018         0   16110.0
    1       7/9/2018         0     619.6
    1       7/23/2018        0     270.4

我的问题在于我必须计算用户何时偿还了他的贷款以及他/她迟到了多少钱,这意味着11000的第一笔借款是在2014年1月9日全额支付的:这里我计算了日期差异在这两个日期之间,这是多少付款延迟,但后来我需要从1/9/2018的信贷中拿走11000并转到下一笔借记,然后计算下次付款的全部时间.

我希望最终得到的结果是:

SubjectID | Date_value | Debit | Credit | PaymentLate |
    1        9/7/2017    11000        0           124
    1        12/7/2017    6000        0           228

因为第1次借记在1/9/201全额支付,并且第2次借记在7/23/2018全额支付了... PaymentLate是借方date_value和信用的运行总额达到足够的钱之间的日期差.

我确实尝试过总计和总和,但是当我在完全支付时开始从信用卡上取走借款时我有问题...换句话说,我没有走得太远.

我正在使用Oracle 11.1.0.7.0企业版.

Answer 1

以下陈述应该做的伎俩:

WITH sum_data AS (SELECT subject_id
                       , date_value
                       , debit
                       , credit
                       , SUM(debit) over(PARTITION BY subject_id 
                                         ORDER BY date_value
                                         ROWS UNBOUNDED PRECEDING) SUM_debit
                       , SUM(credit) over(PARTITION BY subject_id 
                                          ORDER BY date_value
                                          ROWS UNBOUNDED PRECEDING) SUM_credit
                   FROM IncomeTest )
SELECT d.subject_id
     , d.date_value
     , d.debit
     , d.credit
     , GREATEST( (SELECT MIN(date_value) 
                    FROM sum_data d2
                   WHERE d2.SUM_credit >= d.sum_debit
                     AND d2.subject_id  = d.subject_id) - date_value
               ,0) PaymentLate 
  FROM sum_data d
 WHERE debit != 0