使用 Google 脚本循环访问 Google 表格中某个范围内的单元格

Question

我想编写一个脚本，允许我仅突出显示（背景颜色）选定范围内的某些单元格，例如，仅突出显示第 2 列和第 2 行中的单元格，即使我选择整个表格也是如此。

前任：

例如：

For each cell in selected range {
	If selected cell[i][j] is within allowed range {
		cell background color = green
	};
};

我试图完成的代码：

function BackgroundColor() {
  var spreadsheet = SpreadsheetApp.getActive();
  var sheet = spreadsheet.getActiveSheet();
  var range = sheet.getActiveRange();
  var cells = range.getValues();
  var numRows = range.getNumRows();
  var numCols = range.getNumColumns();
  
  for (var i = 0; i < numRows; i++) {
    for (var j = 0; j < numCols; j++) {
      if (range.getValues()[i][j] == '') {
        range.setBackground('#00B050').setFontColor('#ffffff')
      }
    }
  }
  range.setValues(cells);
};

我能够用 VBA 做到这一点：

Sub cmdGreen()

    Dim Cel As Range
    Dim GreenArrayCount As Integer
    Dim InteriorColor As Long, FontColor As Long
    Dim GreenArray() As Variant
    Dim BodyRange As String

    InteriorColor = VBA.RGB(0, 176, 80) 'interior in green
    FontColor = VBA.RGB(255, 255, 255) 'font in white
    GreenArray = Array("COLUMN 2", "ROW 2")
    BodyRange = ActiveSheet.ListObjects(1).DataBodyRange.Address

    For Each Cel In Application.Selection.Cells
        If Not Intersect(Cel, Range(BodyRange)) Is Nothing Then
            For GreenArrayCount = LBound(GreenArray) To UBound(GreenArray)
                If (ActiveSheet.ListObjects(1).HeaderRowRange(Cel.Column).Value _
                    = GreenArray(GreenArrayCount) Or _
                    ActiveSheet.ListObjects(1).DataBodyRange(Cel.Row - 1, 1).Value _
                    = GreenArray(GreenArrayCount)) Then
                    Cel.Interior.Color = InteriorColor
                    Cel.Font.Color = FontColor
                End If
            Next GreenArrayCount
        End If
    Next Cel

End Sub

有人可以帮我吗？

Answer 1

修改后的代码：

function BackgroundColor() {

  var okColumn = [3, 6, 7, 8, 9];
  var spreadsheet = SpreadsheetApp.getActive();
  var sheet = spreadsheet.getActiveSheet();
  var selection = sheet.getSelection();
  var range = sheet.getActiveRange();
  var numRows = range.getNumRows();
  var numCols = range.getNumColumns();
  var startRow = range.getRow();
  var startCol = range.getColumn();

  for (var i = 3; i < numRows; i++) {
    for (var j = 0; j < numCols; j++) {
      for (var k = 0; k <= 4; k++) {
        if ((startRow + i == okRow) || (startCol + j == okColumn[k])) {
          range.getCell(i+1,j+1).setBackground('#00B050').setFontColor('#ffffff')
        }
      }
    }
  }
};

Answer 2

毫无疑问，有很多方法可以提高性能，但这应该可以解决问题。

function BackgroundColor() {
  var okRow = 2;
  var okColumn = 2;
  var spreadsheet = SpreadsheetApp.getActive();
  var sheet = spreadsheet.getActiveSheet();
  var selection = sheet.getSelection();

  //Logger.log('Active Range: ' + selection.getActiveRange().getA1Notation());

  var range = selection.getActiveRange();
  var numRows = range.getNumRows();
  var numCols = range.getNumColumns();
  var startRow = range.getRow();
  var startCol = range.getColumn();
  //Logger.log('row: ' + startRow);
  //Logger.log('col: ' + startCol);
  //Logger.log('num row: ' + numRows);
  //Logger.log('num col: ' + numCols);

  for (var i = 0; i < numRows; i++) {
    for (var j = 0; j < numCols; j++) {
      if ((startRow+i == okRow) || (startCol+j == okColumn)){
        //Logger.log('found: ' + i+' '+j);
        range.getCell(i+1,j+1).setBackground('#00B050').setFontColor('#ffffff')
      }
    }
  }
};

请注意，范围是从 0 开始的，但 getCell 是从 1 开始的。还要注意，我这里的行和列是基于实际的行和列，而不是它们的标签。在您的示例中，okRow 为 4，okColumn 为 3。