Python：将额外的参数传递给 callable

Question

我有以下python代码：

import networkx as nx 

def cost(i, j, d, value1, value2):
    # some operation involving all these values
    return cost


# graph is a networkx graph
# src, dst are integers
# cost is a callable that is passed 3 values automatically i.e. src, dst and d 
# d is a dictionary of edge weights
path = nx.dijkstra_path(graph, src, dst, weight=cost)

现在我想通过两个值value1，并value2给cost功能。

该networkx文件表示，weight可以接受恰好3参数的调用。但我需要value1和value2进行计算。如何才能做到这一点？

编辑 使用 functools 的解决方案效果很好。但是，我的函数在一个类中，如下所示：

import networkx as nx 
import functools
class Myclass:
    def cost(self, i, j, d, value2):
        # some operation involving all these values
        # also need self


    # graph is a networkx graph
    # src, dst are integers
    # cost is a callable that is passed 3 values automatically i.e. src, dst and d 
    # d is a dictionary of edge weights
    # path = nx.dijkstra_path(graph, src, dst, cost)
    cost_partial = functools.partial(cost, self=self, value2=5)
    path = nx.dijkstra_path(graph, src, dst, cost_partial)

使用这种方法，nx.dijkstra_path坚持分配src给self. 因此解释器抱怨self分配了多个值。我需要 self 来计算成本。

Answer 1

您只需要一个包装cost. 一个快速的方法是使用functools.partial.

import functools

def cost(i, j, d, value1, value2):
    'Example function'
    return i, j, d, value1, value2

# This makes a new function which takes all parameters of `cost` except those 
# you've already passed. Here I'm going to set value1 and value2 to 1 and 2 
# respectively.
cost_partial = functools.partial(cost, value1=1, value2=2)

# A new function that only accepts the 3 args i, j, d
cost_partial('i', 'j', 'd')  # --> ('i', 'j', 'd', 1, 2)

# use as
path = nx.dijkstra_path(graph, src, dst, weight=cost_partial)