python 使用包含模式复制文件

Question

我需要使用 python 脚本复制包含模式的文件。由于shutil支持ignore_patterns来忽略文件。有没有任何方法可以包含复制文件的模式。否则我必须明确地编写代码吗？

提前致谢

编辑

from shutil import copytree, ignore_patterns

source=r'SOURCE_PATH'
destination=r'DESTINATION_PATH'
copytree(source, destination, ignore=ignore_patterns('*.txt'))

上面的代码从 dir 复制了除指定格式之外的文件，但我需要如下所示的内容

from shutil import copytree, include_patterns

source=r'SOURCE_PATH'
destination=r'DESTINATION_PATH'
copytree(source, destination, ignore=include_patterns('*.txt'))

Answer 1

下面的解决方案工作正常

 from fnmatch import fnmatch, filter
    from os.path import isdir, join
    from shutil import copytree

    def include_patterns(*patterns):
        """Factory function that can be used with copytree() ignore parameter.

        Arguments define a sequence of glob-style patterns
        that are used to specify what files to NOT ignore.
        Creates and returns a function that determines this for each directory
        in the file hierarchy rooted at the source directory when used with
        shutil.copytree().
        """
        def _ignore_patterns(path, names):
            keep = set(name for pattern in patterns
                                for name in filter(names, pattern))
            ignore = set(name for name in names
                            if name not in keep and not isdir(join(path, name)))
            return ignore
        return _ignore_patterns

    # sample usage

    copytree(src_directory, dst_directory,
         ignore=include_patterns('*.dwg', '*.dxf'))