我正在尝试说明一种特殊情况,其中几个数组的长度应该比正常的短,但是判别式和数组的长度之间没有直接关系。通常情况下,简化的记录如下所示:
type Int_Array is array(Integer range <>);
type My_Record is
record
A : Integer;
B : Integer;
C : Int_Array(1..10);
D : Int_Array(1..6);
end record;
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但是,如果某些判别式为320,则应如下所示:
type My_Record is
record
A : Integer;
B : Integer;
C : Int_Array(1..4);
D : Int_Array(1..2);
end record;
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我一直在玩它,但无法编译任何东西。这是我尝试过的一些方法:
type My_Record(Disc : Positive) is
record
A : Integer;
B : Integer;
C : Int_Array(1..(if Disc = 320 then 4 else 10));
D : Int_Array(1..(if Disc = 320 then 2 else 4));
end record;
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但这会导致错误“约束中的区别必须单独出现”。
如果我尝试:
type My_Record(Disc : Positive) is
record
A : Integer;
B : Integer;
case Disc is
when 320 =>
C : Int_Array(1..4);
D : Int_Array(1..2);
when others =>
C : Int_Array(1..10);
D : Int_Array(1..4);
end case;
end record;
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C和D的定义相互冲突。我还有其他技术可以使用吗?
如果要使用变量.C而.D不管变量如何访问变量,则可以使用访问器函数:
type My_Record (IDisc : Positive) is record
IA, IB : Integer;
case Disc is
when 320 =>
C1 : aliased Int_Array (1 .. 4);
D1 : aliased Int_Array (1 .. 2);
when others =>
C2 : aliased Int_Array (1 .. 10);
D2 : aliased Int_Array (1 .. 4);
end case;
end record;
type Int_Array_Accessor (Data : not null access all Int_Array) is
limited null record with Implicit_Dereference => Data;
function C (Object : in out My_Record) return Int_Array_Accessor is
(Int_Array_Accessor'(if Object.Disc = 320 then
Object.C1'Access else Object.C2'Access));
function D (Object : in out My_Record) return Int_Array_Accessor is
(Int_Array_Accessor'(if Object.Disc = 320 then
Object.D1'Access else Object.D2'Access));
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通过将访问器与一起使用Implicit_Dereference,您可以将值分配为好像是记录字段一样的值。