如何在dict中计算相同的值？

Question

我有一个dict看起来像这样:

"votes": {
    "user1": "yes",
    "user2": "no",
    "user3": "yes",
    "user4": "no",
    "user5": "maybe",
    "user6": "yes"
}

我想要做的是,计算相同的值,以便我知道yes发生了3次,no发生了2次,maybe发生了1次.

我现在做的是:

votes = OrderedDict()
for key, value in vote_dict["votes"].items():
    if value in votes:
        votes[value] += 1
    else:
        votes[value] = 1

它工作正常,但肯定有更好的方法来做到这一点.什么是更pythonic方式来做到这一点？

Answer 1

您可以养活一个可迭代如dict.values到collections.Counter:

from collections import Counter

votes = {"user1": "yes", "user2": "no", "user3": "yes",
         "user4": "no", "user5": "maybe", "user6": "yes"}

res = Counter(votes.values())

print(res)

Counter({'yes': 3, 'no': 2, 'maybe': 1})