使用 Apache POI 获取 Excel 填充颜色

Gra*_*man 1 java excel apache-poi

我正在使用 Apache POI 3.17 阅读 Excel 2013 工作簿。工作簿由用户直接在 Excel 中创建和编辑。然后我运行一个 Java 8 程序,该程序使用 POI 来读取和处理工作簿。

有些单元格是颜色编码的,所以我需要获取填充颜色。在许多情况下,这工作正常,但有一组灰色/银色不起作用,我不确定为什么。

例如,Excel 单元格如下所示:

Excel 示例

我获取填充颜色的代码是:

private String getFillColor(XSSFCell cell) {
    String fColorString = "None";
    if (cell != null) {
        XSSFCellStyle cellStyle = cell.getCellStyle();
        
        short sColorFore = cellStyle.getFillForegroundColor();
        short sColorBack = cellStyle.getFillBackgroundColor();
        XSSFColor xColorFore =  cellStyle.getFillForegroundColorColor();
        XSSFColor xColorBack =  cellStyle.getFillBackgroundColorColor();

        String s = "";
        s += " indexFore=" + sColorFore;
        s += " indexBack=" + sColorBack;
        s += " colorFore=" + ((xColorFore == null) ? "Null" : xColorFore.getARGBHex());
        s += " colorBack=" + ((xColorBack == null) ? "Null" : xColorBack.getARGBHex());
        System.out.println("Cell=" + cell.getAddress() + " " + cell.getStringCellValue() + s);
        
        if (xColorFore != null) {
            fColorString = xColorFore.getARGBHex();
        }8
    }
    return fColorString;
}
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为上面的每个示例 Excel 单元格调用时的结果是:

Cell=BBH52 Pink indexFore=0 indexBack=64 colorFore=FFF79646 colorBack=null

Cell=BBH53 无填充 indexFore=64 indexBack=64 colorFore=Null colorBack=Null

Cell=BBH54 Gray 1 indexFore=0 indexBack=64 colorFore=FFFFFFFF colorBack=null

Cell=BBH55 Gray 2 indexFore=0 indexBack=64 colorFore=FFFFFFFF colorBack=null

Cell=BBH56 Gray 3 indexFore=0 indexBack=64 colorFore=FFFFFFFF colorBack=null

Cell=BBH57 Gray 4 indexFore=0 indexBack=64 colorFore=FFFFFFFF colorBack=null

Cell=BBH58 Gray 5 indexFore=0 indexBack=64 colorFore=FFFFFFFF colorBack=null

Cell=BBH59 White indexFore=0 indexBack=64 colorFore=FFFFFFFF colorBack=null

知道为什么灰色和白色的阴影都转化为 FFFFFFFF 的十六进制值吗?是否有更正确的方法来访问实际填充颜色?谢谢。

Axe*_*ter 7

“Excel 2013 工作簿”是以Office Open XML格式存储的工作簿。那里的颜色可能有一个额外的第 4 个 alpha 通道,但也可能有 ColorType.Tint 属性集。所以实际上所有的灰色阴影都是具有不同设置的RGB白色。例如,在该是:FFFFFFtintxl/styles.xmlGrey 1

...
<fill>
 <patternFill patternType="solid">
  <fgColor theme="0" tint="-0.0499893185216834"/>
  <bgColor indexed="64"/>
 </patternFill>
</fill>
...
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主题颜色 0 是白色,FFFFFF并且tint -0.0499893185216834使白色变暗为灰色。

所以我们必须考虑tint到。幸运apache poi的是, ExtendedColor为此提供了getRGBWithTint方法。

因此,如果已tint设置,以下示例也会正确获取填充颜色:

import java.io.FileInputStream;

import org.apache.poi.ss.usermodel.*;
import org.apache.poi.xssf.usermodel.XSSFColor;
import org.apache.poi.hssf.util.HSSFColor;

public class ReadExcelColorHavingTint {

 private static String getFillColorHex(Cell cell) throws Exception { 
  String fillColorString = "none";
  if (cell != null) {
   CellStyle cellStyle = cell.getCellStyle();
   Color color =  cellStyle.getFillForegroundColorColor();
   if (color instanceof XSSFColor) {
    XSSFColor xssfColor = (XSSFColor)color;
    byte[] argb = xssfColor.getARGB();
    fillColorString = "[" + (argb[0]&0xFF) + ", " + (argb[1]&0xFF) + ", " + (argb[2]&0xFF) + ", " + (argb[3]&0xFF) + "]";
    if (xssfColor.hasTint()) {
     fillColorString += " * " + xssfColor.getTint();
     byte[] rgb = xssfColor.getRGBWithTint();
     fillColorString += " = [" + (argb[0]&0xFF) + ", " + (rgb[0]&0xFF) + ", " + (rgb[1]&0xFF) + ", " + (rgb[2]&0xFF) + "]" ;
    }
   } else if (color instanceof HSSFColor) {
    HSSFColor hssfColor = (HSSFColor)color;
    short[] rgb = hssfColor.getTriplet();
    fillColorString = "[" + rgb[0] + ", " + rgb[1] + ", "  + rgb[2] + "]";
   }
  }
  return fillColorString;
 }

 public static void main(String[] args) throws Exception {
  Workbook workbook = WorkbookFactory.create(new FileInputStream("workbook.xlsx"));
  //Workbook workbook = WorkbookFactory.create(new FileInputStream("workbook.xls"));
  Sheet sheet = workbook.getSheetAt(0);
  for (Row row : sheet) {
   for (Cell cell : row) {

    System.out.println("Cell=" + cell.getAddress() + " " + cell.toString() + " " + getFillColorHex(cell));

   }
  }
 }

}
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