翻译查询以使用Zend_Db_Select

Question

我在翻译此查询以使用ZF时遇到一些问题Zend_Db_Select:

SELECT b.id, b.title, b.description 
FROM memberships AS m
JOIN blogs AS b ON b.id = m.blog_id 
WHERE m.user_id = ? 
ORDER BY m.created
LIMIT 0, 30

(此查询有效并返回结果)

Memberships是blogs和之间的链接表users.这是一件简单的| id | blog_id | user_id |事情.

这是我到目前为止所拥有的:

// $table = Zend_Db_Table instance, $id = a user id
$select = $table->select()
->from(array('m' => 'memberships'), array('b.id', 'b.title', 'b.description'))
->join(array('b' => 'blogs'), 'b.id = m.blog_id')
->where('m.user_id = ?', (int) $id)
->order('m.created DESC')
->limit(0, 30);

这是我得到的(奇怪的(对我而言)错误:

#0: Select query cannot join with another table

发生在第211行D:\...\library\Zend\Db\Table\Select.php.

谢谢你的帮助.

Answer 1

您还可以通过添加setIntegrityCheck(false)来使用传统的$ model-> select()对象,就像这样.

$select = $table->select()
->setIntegrityCheck(false)
->from(array('m' => 'memberships'), array('b.id', 'b.title', 'b.description'))
->join(array('b' => 'blogs'), 'b.id = m.blog_id')
->where('m.user_id = ?', (int) $id)
->order('m.created DESC')
->limit(0, 30);

这会禁用抛出异常的检查:

#0: Select query cannot join with another table

Answer 2

从表对象中检索时,该语句将限于我认为的那个表.这些Zend_Db_Table::select()方法返回一个Zend_Db_Table_Select对象,该对象是该类的子类Zend_Db_Select并强加此限制.试试这个:

$db = Zend_Db::factory( ...options... );
$select = new Zend_Db_Select($adapter);
$select->from( 'my_table_name' )->join( ...

如果您愿意,以下内容应相同:

$db = Zend_Db::factory( ...options... );
$db->select()->from( 'my_table_name' )->join( ...