Ham*_*jan 0 c# regex xml replace linq-to-xml
这不是作业; 我的单元测试需要这个.
样本输入:<rows><row><a>1234</a><b>Hello</b>...</row><row>...</rows>.
样本输出:<rows><row><a>0.0</a><b>0.0</b>...</row><row>...</rows>.
您可以假设文档以该文档开头,<rows>并且该父节点具有名为的子节点<row>.你不知道的节点的名称a,b等等.
额外的功劳:如何使用任意格式良好的"自由格式"XML来完成这项工作?
我用正则表达式尝试了这个:)没有运气.我可以说它"在右边不贪心",但不在左边.谢谢你的帮助.
编辑:这是我尝试过的:
private static string ReplaceValuesWithZeroes(string gridXml)
{
Assert.IsTrue(gridXml.StartsWith("<row>"), "Xml representation must start with '<row>'.");
Assert.IsTrue(gridXml.EndsWith("</row>"), "Xml representation must end with '<row>'.");
gridXml = "<deleteme>" + gridXml.Trim() + "</deleteme>"; // Fake parent.
var xmlDoc = XDocument.Parse(gridXml);
var descendants = xmlDoc.Root.Descendants("row");
int rowCount = descendants.Count();
for (int rowNumber = 0; rowNumber < rowCount; rowNumber++)
{
var row = descendants.ElementAt(0);
Assert.AreEqual<string>(row.Value /* Does not work */, String.Empty, "There should be nothing between <row> and </row>!");
Assert.AreEqual<string>(row.Name.ToString(), "row");
var rowChildren = row.Descendants();
foreach (var child in rowChildren)
{
child.Value = "0.0"; // Does not work.
}
}
// Not the most efficient but still fast enough.
return xmlDoc.ToString().Replace("<deleteme>", String.Empty).Replace("</deleteme>", String.Empty);
}
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XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
foreach (XmlElement el in doc.SelectNodes("//*[not(*)]"))
el.InnerText = "0.0";
xml = doc.OuterXml;
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或者对非空文本节点更具选择性:
foreach (XmlText el in doc.SelectNodes("//text()[.!='']"))
el.InnerText = "0.0";
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