将此XML反序列化为对象的最佳方法

Question

在其他示例中,我看到它与我的相似,有一个根节点,然后是一个数组节点,然后是一堆数组项.我的问题是,我的根节点是我的数组节点,所以我看到的示例似乎对我不起作用,我无法更改XML模式.这是XML:

<articles>  
    <article>
      <guid>7f6da9df-1a91-4e20-8b66-07ac7548dc47</guid>
      <order>1</order>
      <type>deal_abstract</type>
      <textType></textType>
      <id></id>
      <title>Abu Dhabi's IPIC Eyes Bond Sale After Cepsa Buy</title>
      <summary>Abu Dhabi's IPIC has appointed banks for a potential sterling and euro-denominated bond issue, a document showed on Wednesday, after the firm acquired Spain's Cepsa in a $5 billion deal earlier this month...</summary>
      <readmore></readmore>
      <fileName></fileName>
      <articleDate>02/24/2011 00:00:00 AM</articleDate>
      <articleDateType></articleDateType>
    </article>

    <article>
      <guid>1c3e57a0-c471-425a-87dd-051e69ecb7c5</guid>
      <order>2</order>
      <type>deal_abstract</type>
      <textType></textType>
      <id></id>
      <title>Big Law Abuzz Over New China Security Review</title>
      <summary>China’s newly established foreign investment M&amp;A review committee has been the subject of much legal chatter in the Middle Kingdom and beyond. Earlier this month, the State Council unveiled legislative guidance on…</summary>
      <readmore></readmore>
      <fileName></fileName>
      <articleDate>02/23/2011 00:00:00 AM</articleDate>
      <articleDateType></articleDateType>
    </article>  
</articles>

这是我的班级:

public class CurrentsResultsList
{
    public Article[] Articles;
}

public class Article
{
    public string Guid { get; set; }
    public int Order { get; set; }
    public string Type { get; set; }
    public string Title { get; set; }
    public string Summary { get; set; }
    public DateTime ArticleDate { get; set; }
}

这是来自外部API的XML响应.

Answer 1

1. 把它放在视觉工作室里面的xml中
2. 创建xsd架构
3. 使用"C:\ Program Files\Microsoft Visual Studio 8\SDK\v2.0\Bin\xsd.exe""MyXsd.xsd"/ t:lib/l:cs/c /namespace:my.xsd/outputdir:" C:\ testtttt"

现在你准备好了你的c#课程

现在你可以使用这个:

internal class ParseXML 
{
    public static xsdClass ToClass<xsdClass>(XElement ResponseXML)
    {
        return deserialize<xsdClass>(ResponseXML.ToString(SaveOptions.DisableFormatting));
    } 


    private static result deserialize<result>(string XML)
    {
        using (TextReader textReader = new StringReader(XML))
        {
            XmlSerializer xmlSerializer = new XmlSerializer(typeof(result));
            return (result) xmlSerializer.Deserialize(textReader);
        }
    } 
} 

Answer 2

你必须使用一些Xml属性,这个代码应该有希望产生你喜欢的xml,希望它有所帮助:

using System;
using System.IO;
using System.Xml.Serialization;

namespace xmlTest
{
    class Program
    {
        static void Main(string[] args)
        {
            var articles = new Articles();
            articles.ArticleArray = new ArticlesArticle[2]
            {
                new ArticlesArticle()
                    {
                        Guid = Guid.NewGuid(),
                        Order = 1,
                        Type = "deal_abstract",
                        Title = "Abu Dhabi...",
                        Summary = "Abu Dhabi...",
                        ArticleDate = new DateTime(2011,2,24)
                    },
                new ArticlesArticle()
                    {
                        Guid = Guid.NewGuid(),
                        Order = 2,
                        Type = "deal_abstract",
                        Title = "Abu Dhabi...",
                        Summary = "China...",
                        ArticleDate = new DateTime(2011,2,23)
                    },
            };

            var sw = new StringWriter();
            var xmlSer = new XmlSerializer(typeof (Articles));
            var noNamespaces = new XmlSerializerNamespaces();
            noNamespaces.Add("", ""); 
            xmlSer.Serialize(sw, articles,noNamespaces);
            Console.WriteLine(sw.ToString());
        }
    }

    [XmlRoot(ElementName = "articles", Namespace = "", IsNullable = false)]
    public class Articles
    {
        [XmlElement("article")]
        public ArticlesArticle[] ArticleArray { get; set; }
    }

    public class ArticlesArticle
    {
        [XmlElement("guid")]
        public Guid Guid { get; set; }
        [XmlElement("order")]
        public int Order { get; set; }
        [XmlElement("type")]
        public string Type { get; set; }
        [XmlElement("textType")]
        public string TextType { get; set; }
        [XmlElement("id")]
        public int Id { get; set; }
        [XmlElement("title")]
        public string Title { get; set; }
        [XmlElement("summary")]
        public string Summary { get; set; }
        [XmlElement("readmore")]
        public string Readmore { get; set; }
        [XmlElement("fileName")]
        public string FileName { get; set; }
        [XmlElement("articleDate")]
        public DateTime ArticleDate { get; set; }
        [XmlElement("articleDateType")]
        public string ArticleDateType { get; set; }
    }
}