如何在 C++ 中将 cin 设置为类的成员函数？

Question

我正在制作一个小型控制台游戏，我有一个player类，其中包含用于统计数据的私有整数和用于名称的私有字符串。我想要做的是向用户询问他们的姓名，并将其存储到类中的私有name变量中player。我收到一个错误说明：

error: no match for 'operator>>'   
(operand types are 'std::istream {aka std::basic_istream<char>}' and 'void')

这是我的代码：

主程序

#include "Player.h"
#include <iostream>
#include <string>

using namespace std;

int main() {

    Player the_player;
    string name;
    cout << "You wake up in a cold sweat. Do you not remember anything \n";
    cout << "Do you remember your name? \n";

    cin >> the_player.setName(name);
    cout << "Your name is: " << the_player.getName() << "?\n";

    return 0;
}

播放器.h

#ifndef PLAYER_H
#define PLAYER_H
#include <string>
using namespace std;

class Player {
public:
    Player();
    void setName(string SetAlias);
    string getName();

private:
    string name;
};

#endif // PLAYER_H

播放器.cpp

#include "Player.h"
#include <string>
#include <iostream>

Player::Player() {

}

void Player::setName(string setAlias) {
    name = setAlias;
}

string Player::getName() {
    return name;
}

Answer 1

setName函数的返回类型是void，而不是string。因此，您必须首先将变量存储在 a 中string，然后将其传递给函数。

#include "Player.h"
#include <iostream>
#include <string>

using namespace std;

int main() {
  Player the_player;

  cout << "You wake up in a cold sweat. Do you not remember anything \n";
  cout << "Do you remember your name? \n";

  string name;
  cin >> name;

  the_player.setName(name);

  cout << "Your name is: " << the_player.getName() << "?\n";

  return 0;
}