suy*_*esh 5 ruby-on-rails ruby-on-rails-5 graphql graphql-ruby
我有查询类型
Types::QueryType = GraphQL::ObjectType.define do
name 'Query'
field :allProjects, function: Resolvers::Projects
end
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像这样的解析器
require 'search_object/plugin/graphql'
module Resolvers
class Projects
include SearchObject.module(:graphql)
type !types[Types::ProjectType]
scope { Project.all }
ProjectFilter = GraphQL::InputObjectType.define do
name 'ProjectFilter'
argument :OR, -> { types[ProjectFilter] }
argument :description_contains, types.String
argument :title_contains, types.String
end
option :filter, type: ProjectFilter, with: :apply_filter
option :first, type: types.Int, with: :apply_first
option :skip, type: types.Int, with: :apply_skip
def apply_first(scope, value)
scope.limit(value)
end
def apply_skip(scope, value)
scope.offset(value)
end
def apply_filter(scope, value)
branches = normalize_filters(value).reduce { |a, b| a.or(b) }
scope.merge branches
end
def normalize_filters(value, branches = [])
scope = Project.all
scope = scope.where('description ILIKE ?', "%#{value['description_contains']}%") if value['description_contains']
scope = scope.where('title ILIKE ?', "%#{value['title_contains']}%") if value['title_contains']
branches << scope
value['OR'].reduce(branches) { |s, v| normalize_filters(v, s) } if value['OR'].present?
branches
end
end
end
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我想在解析器中访问 current_user,这样我就可以访问 current_user.projects 而不是 Project.all。我对 graphql 和学习非常陌生。
一切正常,但我只需要了解如何摆脱解析器中的 ctx 的整个流程。
首先,您需要current_user
在上下文中设置。这发生在你的 GraphqlController 中。
class GraphqlController < ApplicationController
before_action :authenticate_user!
def execute
variables = ensure_hash(params[:variables])
query = params[:query]
operation_name = params[:operationName]
context = {
current_user: current_user,
}
result = HabitTrackerSchema.execute(query, variables: variables, context: context, operation_name: operation_name)
render json: result
rescue => e
raise e unless Rails.env.development?
handle_error_in_development e
end
# ...
end
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完成后,您current_user
只需编写以下内容即可从查询(或突变)访问:
context[:current_user]
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为了让事情变得更简单,您可以向( ) 添加一个current_user
方法,然后您就可以从该方法中进行调用。Types::BaseObject
app/graphql/types/base_object.rb
current_user
#resolve
module Types
class BaseObject < GraphQL::Schema::Object
field_class Types::BaseField
def current_user
context[:current_user]
end
end
end
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