用React过滤对象列表

Question

这可能是一个克隆帖子，但在我的情况下我没有找到任何解决方案。我有一个对象列表：

export default function() {
  return [
    {name: 'Mark Teer Stegen'},
    {name: 'Nelson Semedo'},
    {name: 'Gerrard Pique'},
    {name: 'Ivan Rakitic'},
    {name: 'Sergio Busquets'},
    {name: 'Denis Suarez'},
    {name: 'Coutinho'},
    {name: 'Luis Suarez'},
    {name: 'Lionel Messi'},
    {name: 'Dembele'},
    {name: 'Malcom'}
  ]
}

我将其导入到组件，分配给状态并在下面的组件中显示。

import React, {Component} from 'react';
import {connect} from 'react-redux';

class Barca extends Component{
  constructor(props){
    super(props);

    this.state = {
      players: this.props.players,
      player: '' //empty to set as an input
    }
  }

  onChange(e){
    this.setState({
      player: e.target.value
    });
    console.log(this.state.player);
  }
  renderList(){
    return this.state.players.map((player) => {
      return(
        <tr key={player.name}>
          <td>{player.name}</td>
        </tr>
      );
    });
  }
  render(){
    return(
      <div className="col-sm-6 table-col table-responsive">
        <input
          type="text"
          value={this.state.player}
          onChange={this.onChange.bind(this)}
        />
        <table className="table table-striped">
          <thead>
            <tr>
              <th className="text-center">
                FC Barcelona
              </th>
            </tr>
          </thead>
          <tbody>
            {this.renderList()}
          </tbody>
        </table>
      </div>
    );
  }
}

const mapStateToProps = (state) => {
  return {
    players: state.reducerBarca
   };
};


export default connect(mapStateToProps)(Barca);

清单看起来像这样

问题是我想按输入值过滤我的球员名单。我在这里做了一些研究，只在Array中发现了过滤，而不像在Objects列表中那样。

我现在所做的是：

1. 显示球员名单
2. 从输入中获取值并在每个书面字母后显示
3. 如何通过输入的术语显示我的列表？

---

谢谢大家！我已移除玩家状态

constructor(props){
    super(props);

    this.state = {
      //players: this.props.players <-- Stupid thing
      player: '' //empty to set as an input
    }
  }

并重写我的renderList()功能

return this.props.players.filter(player =>
        player.name.toLowerCase().includes(this.state.player.toLowerCase())).map(searchedPlayers => {
          return(
            <tr key={searchedPlayers.name}>
              <td>{searchedPlayers.name}</td>
            </tr>
          );
        })
    }

Answer 1

this.state.players.filter(player => player.name.includes(this.state.player))

如果您想映射它们而不是仅过滤状态...

this.state.players.filter(player => 
player.name.includes(this.state.player)).map(searchedPlayers => {
  return(
    <tr key={searchedPlayers.name}>
      <td>{searchedPlayers.name}</td>
    </tr>
  );
})

请注意，您也可以直接从道具进行渲染而无需设置状态（以避免每次用户键入时都重新渲染）

this.state.players

与

this.props.players