Adr*_*ver 6 reactjs react-native
我在上下文API中使用React-Native-Navigation。
我在下面用HOC组件包装屏幕。
const ProviderWrap = Comp => props => (
<Provider>
<Comp {...props} />
</Provider>
);
Navigation.registerComponent('app.AuthScreen', () => ProviderWrap(AuthScreen));
Navigation.registerComponent('app.FindPlaceScreen', () => ProviderWrap(FindPlaceScreen));
Navigation.registerComponent('app.SharePlaceScreen', () => ProviderWrap(SharePlaceScreen));
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这是我的提供者组件
class Provider extends Component {
state = {
placeName: 'hello',
image: 'https://images.unsplash.com/photo-1534075786808-9b819c51f0b7?ixlib=rb-0.3.5&ixid=eyJhcHBfaWQiOjEyMDd9&s=4dec0c0b139fb398b714a5c8264b4a9a&auto=format&fit=crop&w=934&q=80',
places: [],
}
textInputHandler = (text) => {
this.setState({
placeName: text,
})
}
searchInputHandler = (text) => {
const SearchedPlace = this.state.places.filter(place => {
return place.name.includes(text)
})
this.setState(prevState => {
return {
places: SearchedPlace,
}
})
}
placeSubmitHandler = () => {
if (this.state.placeName) {
this.setState(prevState => {
return {
places: [...prevState.places, {
name: prevState.placeName,
image: prevState.image,
}],
placeName: '',
}
})
} else {
return;
}
}
placeDeleteHandler = (id, deleteModal) => {
const newPlaces = this.state.places.filter((place, index) => {
return index !== id
})
this.setState({
places: newPlaces,
})
deleteModal();
}
render() {
return (
<GlobalContext.Provider value={{
state: this.state,
textInputHandler: this.textInputHandler,
placeSubmitHandler: this.placeSubmitHandler,
placeDeleteHandler: this.placeDeleteHandler,
searchInputHandler: this.searchInputHandler,
}}>
{this.props.children}
</GlobalContext.Provider>
)
}
}
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我的问题是屏幕之间不共享上下文状态。在我的上下文状态中,我在placeplaceScreen中添加了一个places数组,该数组工作正常,但是当我转到FindPlaceScreen时,上下文状态places为空。好像我每个屏幕都有两个单独的上下文。
这是一个单例对象的示例,您可以使用 es6 类也有很多实现... es6 示例
var SingletonState = (function () {
var state;
function createState() {
return {someKey:'what ever'};
}
return {
getState: function () {
if (!state) {
state = createState();
}
return state;
}
};
})();
// usage
var state1 = SingletonState.getState();
var state2 = SingletonState.getState();
console.log("Same state? " + (state1 === state2));
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