如何遍历JavaScript对象的深层嵌套属性？

Question

我有一个具有3级嵌套的JavaScript对象.我很难从第3级嵌套中获取值.

我已经对SO进行了一些研究并得到了基本的循环,但我似乎无法超越第一级.

这是我的代码

var customers = {
   "cluster": [{
      "id": "cluster1.1",
      "color": "blue",
      "flights": "784",
      "profit": "524125",
      "clv": "2364",
      "segment": [{
         "id": "segment1.1",
         "color": "green",
         "flights": "82",
         "profit": "22150",
         "clv": "1564",
         "node": [{
            "id": "node1.1",
            "color": "orange",
            "xpos": "1",
            "ypos": "1"
         }, {
            "id": "node1.2",
            "color": "orange",
            "xpos": "1",
            "ypos": "2"
         }, {
            "id": "node1.3",
            "color": "orange",
            "xpos": "1",
            "ypos": "3"
         }, {
            "id": "node1.4",
            "color": "orange",
            "xpos": "1",
            "ypos": "4"
         }]
      }, {
         "id": "segment1.2",
         "color": "red",
         "flights": "2",
         "profit": "2150",
         "clv": "1564",
         "node": [{
            "id": "node2.1",
            "color": "tan",
            "xpos": "2",
            "ypos": "1"
         }, {
            "id": "node2.2",
            "color": "tan",
            "xpos": "2",
            "ypos": "2"
         }, {
            "id": "node2.3",
            "color": "tan",
            "xpos": "2",
            "ypos": "3"
         }, {
            "id": "node2.4",
            "color": "tan",
            "xpos": "2",
            "ypos": "4"
         }]
      }]
   }, {
      "id": "cluster1.2",
      "flights": "4",
      "profit": "5245",
      "clv": "2364",
      "segment": [{
         "id": "segment1.2",
         "flights": "2",
         "profit": "2150",
         "clv": "1564",
         "node": [{
            "id": "node3.1",
            "xpos": "3",
            "ypos": "1"
         }, {
            "id": "node3.2",
            "xpos": "3",
            "ypos": "2"
         }, {
            "id": "node3.3",
            "xpos": "3",
            "ypos": "3"
         }, {
            "id": "node3.4",
            "xpos": "3",
            "ypos": "4"
         }]
      }]
   }, {
      "id": "cluster1.3",
      "flights": "10",
      "profit": "456978",
      "clv": "548",
      "segment": [{
         "id": "segment1.3",
         "flights": "2",
         "profit": "2150",
         "clv": "1564",
         "node": [{
            "id": "node4.1",
            "xpos": "4",
            "ypos": "1"
         }, {
            "id": "node4.2",
            "xpos": "4",
            "ypos": "2"
         }, {
            "id": "node4.3",
            "xpos": "4",
            "ypos": "3"
         }, {
            "id": "node4.4",
            "xpos": "4",
            "ypos": "4"
         }]
      }]
   }]
};

如何在节点内循环并检索xpos和ypos？

Answer 1

你有一个customers存储数组的object()cluster,你可以迭代

var i, cluster;
for (i = 0; i < customers.cluster.length; i++)
{
  cluster = customers.cluster[i];
}

cluster有一个存储的数组segment,您可以在其中迭代:

var j, segment;
for (j = 0; j < cluster.segment.length; j++)
{
  segment = cluster.segment[j];
}

segment有一个存储的数组node,您可以在其中迭代:

var k, node;
for (k = 0; k < segment.node.length; k++)
{
  node = segment.node[k];
}

您可以将所有这些组合在一起,通过组合这些循环来迭代客户中每个集群的每个段的每个节点:

var i, cluster, j, segment, k, node;
for (i = 0; i < customers.cluster.length; i++)
{
  cluster = customers.cluster[i];

  for (j = 0; j < cluster.segment.length; j++)
  {
    segment = cluster.segment[j];

    for (k = 0; k < segment.node.length; k++)
    {
      node = segment.node[k];
      //access node.xpos, node.ypos here
    }
  }
}