use*_*720 5 swagger swagger-2.0
我已经集成了 Swagger,以使用 Spring Boot 为 Spring REST 应用程序生成 API 文档。它运行良好,当我点击 URL 时,我可以看到生成的 API 文档:http://localhost:8080/test/swagger-ui.html 我的问题是如何限制对 API 的访问?基于硬编码用户名和密码的基本身份验证至少在开始时应该足够好。我使用 Maven 添加“swagger2”依赖项。
这是 pom.xml:
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-swagger2</artifactId>
<version>2.7.0</version>
</dependency>
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-swagger-ui</artifactId>
<version>2.7.0</version>
</dependency>
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这是招摇的配置:
@Configuration
@EnableSwagger2
public class SwaggerConfig {
@Bean
public Docket api() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.basePackage("com.eeocd.test.ws.resource"))
.build();
}
}
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小智 2
您可以通过将 securityScheme 和 securityContext 添加到 Docket 对象来启用身份验证。
@Configuration
@EnableSwagger2
public class SwaggerConfig {
@Bean
public Docket api() {
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.basePackage("com.eeocd.test.ws.resource"))
.build()
.securitySchemes(newArrayList(basicAuth()))
.securityContexts(newArrayList(securityContext()));
}
private BasicAuth basicAuth() {
BasicAuth ba = new BasicAuth("basic");
return ba;
}
private SecurityContext securityContext() {
return SecurityContext.builder()
.securityReferences(defaultAuth())
.forPaths(apiPaths())
.build();
}
private List<SecurityReference> defaultAuth() {
AuthorizationScope authorizationScope = new AuthorizationScope("global", "accessEverything");
AuthorizationScope[] authorizationScopes = new AuthorizationScope[1];
authorizationScopes[0] = authorizationScope;
return newArrayList(new SecurityReference("basic", authorizationScopes));
}
private Predicate<String> apiPaths() {
return or(regex("/api/v1.*")
);
}
}
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