麻烦在Visual Studio中调试c ++代码指针

Question

我想列出列出的数组的每个成员及其相应的寄存器地址位置.这是我的代码

    // PointerDeferenceTest.cpp : Defines the entry point for the console application.
    //
    #include "stdafx.h"
    #include <iostream>
    using namespace std;
    int main()
    {
        int x=0, y=0;
        int *px, *py;

        int number[15] = {-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9};
        while (x<14)
        {
            px = &x;
            py = number+x;
            cout << x+1 << ", " << px << ", " << *px << ", " << py << ", " <<  *py << ", " << py++ << ", " << *(py++) << ", " << *(++py) << "  \n";
            ++x;
        }
        return 0;

}

以64位运行会产生以下意外结果

1, 000000D7532FF874, 0, 000000D7532FF904, -1, 000000D7532FF900, -3, -1
2, 000000D7532FF874, 1, 000000D7532FF908, 0, 000000D7532FF904, -2, 0
3, 000000D7532FF874, 2, 000000D7532FF90C, 1, 000000D7532FF908, -1, 1
4, 000000D7532FF874, 3, 000000D7532FF910, 2, 000000D7532FF90C, 0, 2
5, 000000D7532FF874, 4, 000000D7532FF914, 3, 000000D7532FF910, 1, 3
6, 000000D7532FF874, 5, 000000D7532FF918, 4, 000000D7532FF914, 2, 4
7, 000000D7532FF874, 6, 000000D7532FF91C, 5, 000000D7532FF918, 3, 5
8, 000000D7532FF874, 7, 000000D7532FF920, 6, 000000D7532FF91C, 4, 6
9, 000000D7532FF874, 8, 000000D7532FF924, 7, 000000D7532FF920, 5, 7
10, 000000D7532FF874, 9, 000000D7532FF928, 8, 000000D7532FF924, 6, 8
11, 000000D7532FF874, 10, 000000D7532FF92C, 9, 000000D7532FF928, 7, 9
12, 000000D7532FF874, 11, 000000D7532FF930, 0, 000000D7532FF92C, 8, 0
13, 000000D7532FF874, 12, 000000D7532FF934, -858993460, 000000D7532FF930, 9, -858993460
14, 000000D7532FF874, 13, 000000D7532FF938, -858993460, 000000D7532FF934, 0, -858993460

我无法弄清楚我做错了什么.第4列(py)开始列出数组中的第4项.但是代码设置为读取第一个(数字[0]).我很有趣W10 Visual studio社区2017编译64位

更新1:回应PhoenixBlue的评论.修改了数组样本使用不同的数字.

更新2: 这是我的预期结果

   1, 000000D7532FF874, 0, 000000D7532FF904, -4, 000000D7532FF900, -3, -1
    2, 000000D7532FF874, 1, 000000D7532FF908, -3, 000000D7532FF904, -2, 0
    3, 000000D7532FF874, 2, 000000D7532FF90C, -2, 000000D7532FF908, -1, 1
    4, 000000D7532FF874, 3, 000000D7532FF910, -1, 000000D7532FF90C, 0, 2
    5, 000000D7532FF874, 4, 000000D7532FF914, 0, 000000D7532FF910, 1, 3
    6, 000000D7532FF874, 5, 000000D7532FF918, 1, 000000D7532FF914, 2, 4
    7, 000000D7532FF874, 6, 000000D7532FF91C, 2, 000000D7532FF918, 3, 5
    8, 000000D7532FF874, 7, 000000D7532FF920, 3, 000000D7532FF91C, 4, 6
    9, 000000D7532FF874, 8, 000000D7532FF924,4, 000000D7532FF920, 5, 7
    10, 000000D7532FF874, 9, 000000D7532FF928, 5, 000000D7532FF924, 6, 8
    11, 000000D7532FF874, 10, 000000D7532FF92C, 6, 000000D7532FF928, 7, 9
    12, 000000D7532FF874, 11, 000000D7532FF930, 7, 000000D7532FF92C, 8, 0
    13, 000000D7532FF874, 12, 000000D7532FF934, 8, 000000D7532FF930, 9, -858993460
    14, 000000D7532FF874, 13, 000000D7532FF938, 9, 000000D7532FF934, 0, -858993460

Answer 1

这段代码是个问题py++ << ", " << *(py++) << ", " << *(++py).

在C++中,您不应在同一表达式中使用同一变量的多个增量.

像这样重写你的代码

cout << x+1 << ", " << px << ", " << *px << ", " << py << ", " <<  *py << ", ";
cout << py++ << ", ";
cout << *(py++) << ", ";
cout << *(++py) << "  \n";

这应该解决一些问题,尽管Msalters说你也有其他问题.