如何在 Java 中压缩目录的内容

Question

我在java下面使用，但是当它压缩时，它会创建一个目录并将该目录中的所有内容压缩。例如。如果我有一个名为“Directory”的文件夹并且我想将内容压缩到一个压缩文件中，则在压缩文件中它会创建一个文件夹 testZip 并在其中包含文件。我需要压缩文件中的所有文件，而不是父目录中的所有文件。请帮忙。或建议是否有任何其他方式。

package folderZip;

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;

import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

public class ZipFolder {
    public ZipFolder() {  
    }  


    public static void main(String[] args) throws Exception {
        ZipFolder obj = new ZipFolder();
        obj.zipFolder("C:\\Drive\\temp\\testZip","C:\\Drive\\temp\\FolderZiper.zip");       
    }


     public void zipFolder(String srcFolder,
                                 String destZipFile) throws Exception {
        ZipOutputStream zip = null;
        FileOutputStream fileWriter = null;

        fileWriter = new FileOutputStream(destZipFile);
        zip = new ZipOutputStream(fileWriter);

        addFolderToZip("", srcFolder, zip);

        zip.flush();
        zip.close();

    }

    private void addFileToZip(String path, String srcFile,
                                     ZipOutputStream zip) throws Exception {

        File folder = new File(srcFile);
        if (folder.isDirectory()) {
            addFolderToZip(path, srcFile, zip);
        } else {
            byte[] buf = new byte[1024];
            int len;
            FileInputStream in = new FileInputStream(srcFile);
            zip.putNextEntry(new ZipEntry(path + "/" + folder.getName()));
            while ((len = in.read(buf)) > 0) {
                zip.write(buf, 0, len);
            }
        }
    }

    private void addFolderToZip(String path, String srcFolder,
                                       ZipOutputStream zip) throws Exception {
        File folder = new File(srcFolder);

        for (String fileName : folder.list()) {
            if (path.equals("")) {
                addFileToZip(folder.getName(), srcFolder + "/" + fileName,
                             zip);
            } else {
                addFileToZip(path + "/" + folder.getName(),
                             srcFolder + "/" + fileName, zip);
            }
        }
    }
}

Answer 1

因此，如果我理解正确的话，您想要的是，而不是出现在 Zip 文件中的目标文件夹，其中的所有文件都应以 Zip 文件中的“/”开头。

例如，如果你有

FolderToZip/
    TestFile1.txt
    TestFile2.txt
    TestFile3.txt
    SomeSubFolder/
        TestFile4.txt
        TestFile5.txt
        TestFile6.txt

Zip 文件的内容应包含

TestFile1.txt
TestFile2.txt
TestFile3.txt
SomeSubFolder/
    TestFile4.txt
    TestFile5.txt
    TestFile6.txt

为此，您需要保留对“开始”文件夹的引用，并从您添加的文件中删除它的路径，以创建 ZipEntry.

为简单起见，我将您的代码更改为支持File而不是String，它只会让整个事情变得不那么混乱。

但是魔法出现在这里……

FileInputStream in = new FileInputStream(srcFile);
String name = srcFile.getPath();
name = name.replace(rootPath.getPath(), "");
System.out.println("Zip " + srcFile + "\n to " + name);
zip.putNextEntry(new ZipEntry(name));

rootPath是初始文件夹（C:\\Drive\\temp\\testZip"在您的示例中），srcFile是要添加的文件。

可运行示例...

import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;


public class ZipFolder {

    public ZipFolder() {
    }

    public static void main(String[] args) throws Exception {
        ZipFolder obj = new ZipFolder();
        obj.zipFolder(new File("/Users/shanewhitehead/exports"),
                new File("FolderZiper.zip"));
    }

    public void zipFolder(File srcFolder, File destZipFile) throws Exception {
        try (FileOutputStream fileWriter = new FileOutputStream(destZipFile);
                ZipOutputStream zip = new ZipOutputStream(fileWriter)) {

            addFolderToZip(srcFolder, srcFolder, zip);
        }
    }

    private void addFileToZip(File rootPath, File srcFile, ZipOutputStream zip) throws Exception {

        if (srcFile.isDirectory()) {
            addFolderToZip(rootPath, srcFile, zip);
        } else {
            byte[] buf = new byte[1024];
            int len;
            try (FileInputStream in = new FileInputStream(srcFile)) {
                String name = srcFile.getPath();
                name = name.replace(rootPath.getPath(), "");
                System.out.println("Zip " + srcFile + "\n to " + name);
                zip.putNextEntry(new ZipEntry(name));
                while ((len = in.read(buf)) > 0) {
                    zip.write(buf, 0, len);
                }
            }
        }
    }

    private void addFolderToZip(File rootPath, File srcFolder, ZipOutputStream zip) throws Exception {
        for (File fileName : srcFolder.listFiles()) {
            addFileToZip(rootPath, fileName, zip);
        }
    }
}

我还使用try-with-resources清理了您的资源管理