var fruits = [];
fruits.push("lemon", "lemon", "lemon", "lemon");
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而不是推动相同的元素,如何像这样写一次:
fruits.push("lemon" * 4 times)
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Cer*_*nce 24
对于原语,请使用.fill:
var fruits = new Array(4).fill('Lemon');
console.log(fruits);Run Code Online (Sandbox Code Playgroud)
对于非基元,不要使用fill,因为那时数组中的所有元素都将引用内存中的同一个对象,因此数组中一个项的突变将影响数组中的每个项 - 相反,在每次迭代时显式创建对象,可以用Array.from:
const fruits = new Array(4).fill({ Lemon: 'Lemon' });
fruits[0].Apple = 'Apple';
console.log(JSON.stringify(fruits));
// The above doesn't work for the same reason that the below doesn't work:
// there's only a single object in memory
const obj = { Lemon: 'Lemon' };
const fruits2 = [];
fruits2.push(obj);
fruits2.push(obj);
fruits2.push(obj);
fruits2.push(obj);
fruits2[0].Apple = 'Apple';
console.log(JSON.stringify(fruits2));Run Code Online (Sandbox Code Playgroud)