Abd*_*mac 2 python selenium web-scraping selenium-webdriver
我正在使用 Python 和 Selenium 抓取这个网站。我有代码工作,但它目前只抓取第一页,我想遍历所有页面并将它们全部抓取,但它们以一种奇怪的方式处理分页,我将如何浏览页面并逐个抓取它们?
分页 HTML:
<div class="pagination">
<a href="/PlanningGIS/LLPG/WeeklyList/41826123,1" title="Go to first page">First</a>
<a href="/PlanningGIS/LLPG/WeeklyList/41826123,1" title="Go to previous page">Prev</a>
<a href="/PlanningGIS/LLPG/WeeklyList/41826123,1" title="Go to page 1">1</a>
<span class="current">2</span>
<a href="/PlanningGIS/LLPG/WeeklyList/41826123,3" title="Go to page 3">3</a>
<a href="/PlanningGIS/LLPG/WeeklyList/41826123,4" title="Go to page 4">4</a>
<a href="/PlanningGIS/LLPG/WeeklyList/41826123,3" title="Go to next page">Next</a>
<a href="/PlanningGIS/LLPG/WeeklyList/41826123,4" title="Go to last page">Last</a>
</div>
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刮刀:
import re
import json
import requests
from selenium import webdriver
from selenium.webdriver.support.ui import Select
from selenium.webdriver.chrome.options import Options
options = Options()
# options.add_argument('--headless')
options.add_argument("start-maximized")
options.add_argument('disable-infobars')
driver=webdriver.Chrome(chrome_options=options,
executable_path=r'/Users/weaabduljamac/Downloads/chromedriver')
url = 'https://services.wiltshire.gov.uk/PlanningGIS/LLPG/WeeklyList'
driver.get(url)
def getData():
data = []
rows = driver.find_element_by_xpath('//*[@id="form1"]/table/tbody').find_elements_by_tag_name('tr')
for row in rows:
app_number = row.find_elements_by_tag_name('td')[1].text
address = row.find_elements_by_tag_name('td')[2].text
proposals = row.find_elements_by_tag_name('td')[3].text
status = row.find_elements_by_tag_name('td')[4].text
data.append({"CaseRef": app_number, "address": address, "proposals": proposals, "status": status})
print(data)
return data
def main():
all_data = []
select = Select(driver.find_element_by_xpath("//select[@class='formitem' and @id='selWeek']"))
list_options = select.options
for item in range(len(list_options)):
select = Select(driver.find_element_by_xpath("//select[@class='formitem' and @id='selWeek']"))
select.select_by_index(str(item))
driver.find_element_by_css_selector("input.formbutton#csbtnSearch").click()
all_data.extend( getData() )
driver.find_element_by_xpath('//*[@id="form1"]/div[3]/a[4]').click()
driver.get(url)
with open( 'wiltshire.json', 'w+' ) as f:
json.dump( all_data, f )
driver.quit()
if __name__ == "__main__":
main()
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在继续自动化任何场景之前,请始终写下您将要执行的手动步骤来执行场景。您想要的手动步骤(我从问题中了解到)是-
1) 前往网站 - https://services.wiltshire.gov.uk/PlanningGIS/LLPG/WeeklyList
2) 选择第一周选项
3)点击搜索
4) 获取每一页的数据
5)再次加载url
6) 选择第二周选项
7)点击搜索
8) 获取每一页的数据
.. 等等。
您有一个循环来选择不同的周,但在周选项的每个循环迭代中,您还需要包含一个循环来迭代所有页面。由于您没有这样做,因此您的代码仅返回第一页的数据。
另一个问题是您如何定位“下一步”按钮 -
driver.find_element_by_xpath('//*[@id="form1"]/div[3]/a[4]').click()
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您正在选择第四个<a>元素,这当然不是健壮的,因为在不同的页面中,下一步按钮的索引会有所不同。相反,使用这个更好的定位器 -
driver.find_element_by_xpath("//a[contains(text(),'Next')]").click()
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创建循环的逻辑将遍历页面 -
首先,您将需要页数。我通过在“下一步”按钮<a> 之前找到 来做到这一点。根据下面的屏幕截图,很明显该元素的文本将等于页数 -
我使用以下代码做到了-
number_of_pages = int(driver.find_element_by_xpath("//a[contains(text(),'Next')]/preceding-sibling::a[1]").text)
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现在,一旦您的页数为number_of_pages,您只需单击“下一步”按钮number_of_pages - 1次!
您的main功能的最终代码-
def main():
all_data = []
select = Select(driver.find_element_by_xpath("//select[@class='formitem' and @id='selWeek']"))
list_options = select.options
for item in range(len(list_options)):
select = Select(driver.find_element_by_xpath("//select[@class='formitem' and @id='selWeek']"))
select.select_by_index(str(item))
driver.find_element_by_css_selector("input.formbutton#csbtnSearch").click()
number_of_pages = int(driver.find_element_by_xpath("//a[contains(text(),'Next')]/preceding-sibling::a[1]").text)
for j in range(number_of_pages - 1):
all_data.extend(getData())
driver.find_element_by_xpath("//a[contains(text(),'Next')]").click()
time.sleep(1)
driver.get(url)
with open( 'wiltshire.json', 'w+' ) as f:
json.dump( all_data, f )
driver.quit()
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