尝试从FormRun检索数据源时获取null

Red*_*Wei 2 x++ axapta

我有2个表单,让我们调用表单A和B.在表单A中,我有一个按钮(空白按钮),当单击该按钮时,它将重定向到带有参数的表单B,该参数将注入表单B的数据源我无法检索表单B的数据源,它总是返回null.

[FormControlEventHandler(formControlStr(htVehicleListPage, FormCommandButtonControl1), FormControlEventType::Clicked)]
    public static void FormCommandButtonControl1_OnClicked(FormControl sender, FormControlEventArgs e)
    {
        FormDataSource htVehicleTable= sender.formRun().dataSource(formDataSourceStr(htVehicleListPage,htVehicleTable));
        htVehicleTable record=htVehicleTable.cursor();
        info(int2Str(record.htVehicleID)); //result: some legit ID.
        Args argsObj=new Args();
        argsObj.name(formStr(htVehicleMaintenanceDetails));
        FormRun formRunObj=new FormRun(argsObj);
        FormDataSource openningFormDataSource =formRunObj.dataSource(formDataSourceStr(htVehicleMaintenanceDetails,htVehicleMaintenance)); //result: openningFormDataSource is null, however, formRunObj is not null.
        Query queryObj=new Query();
        openningFormDataSource.query(queryObj);
        QueryBuildDataSource queryBuildDataSourceObj=queryObj.addDataSource(tableNum(htVehicleMaintenance));
        queryBuildDataSourceObj.addRange(fieldNum(htVehicleMaintenance,htVehicleID)).value(strFmt("htVehicleMaintenance.htVehicleID=%1",record.htVehicleID));
        formRunObj.init();
        formRunObj.run(); //if we inorge the null error it will show a form here
        formRunObj.wait();
    }
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Ale*_*tny 5

FormRun只是......它是运行形式的对象.openningFormDataSource因为您之前调用它formRunObj.init();并且表单尚未运行,您将为null .

它会Form.init(),然后它Form...Datasource.init(),然后Form.run()基本上.

向上移动formRunObj.init()并再试一次.