JSON.Stringfy方法的替换参数不适用于嵌套对象

Muh*_*gan 6 javascript typescript

我有一个对象,我想将此对象的简化版本发送到服务器.

{
 "fullName": "Don Corleone",
 "actor": {
  "actorId": 2,
  "name": "Marlon",
  "surname": "Brando",
  "description": "Marlon Brando is widely considered the greatest movie actor of all time... ",
  "heroList": [],
  "photo": "C:\\projects\\files\\actor\\1532955376934.png"
 },
 "heroProfilePhoto": "data:image/png;base64,/9j/...
 "production": {
  "title": "The Godfather",
  "imdbRate": 9.2,
  "genre": "8",
  "releaseDate": "1972-03-23T21:00:00.000Z",
  "director": "Francis Ford Coppola",
  "writer": "Mari Puzo",
  "detail": "The aging patriarch of an organized crime dynasty transfers control of his clandestine empire to his reluctant son."
 }
}"
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我有两个问题::

1)是否有可能提取像这样用替代品参数JSON.stringify()

 {
  "fullName": "Don Corleone",
  "actor": {
   "actorId": 2
   }
}"
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2)至少我可以提取像这样用替代品参数JSON.stringify()

{
 "fullName": "Don Corleone",
 "actor": {
  "actorId": 2,
  "name": "Marlon",
  "surname": "Brando",
  "description": "Marlon Brando is widely considered the greatest movie actor of all time... ",
  "heroList": [],
  "photo": "C:\\projects\\files\\actor\\1532955376934.png"
 },
}"
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当我这样使用时,没关系:

JSON.stringify(hero, ['fullName']) 结果 - > "{"fullName":"Don Corleone"}"

但是这个 :

JSON.stringify(hero, ['fullName', 'actor']) 结果 - > "{"fullName":"Don Corleone","actor":{}}"

为什么演员财产是空的?

Woo*_*jin 6

JSON.stringify要求您传递您想要返回的所有数据.'actor'靠自己是不够的.

你要:

JSON.stringify(hero, ['fullName', 'actor', 'actorId'])

编辑

所以我做了一些测试,我很好奇如果actorId在父对象中也存在会发生什么,结果是在.

actorIdactorId存在于actor对象内部和父对象内部的情况下,JSON.stringify()返回两个字段.如果您不希望出现这种情况,则必须根据需要创建更复杂的函数,并将其传递给JSON.stringify(),如此处所述

以下是一些例子:

var json = {
    key1: "Value for key1 in parent",
    key2: {
        key3: "Value for key3 in child",
        key4: "Value for key4 in child"
    },
    key4: "Value for key4 in parent"
}

var out1 = JSON.stringify(json, ['key1', 'key3'])
/*
out1 = {
    key1: "Value for key1 in parent"
} // No key3!
*/


var out2 = JSON.stringify(json, ['key1', 'key2', 'key3'])
/*
out2 = {
    key1: "Value for key1 in parent",
    key2: {
        key3: "Value for key3 in child"
    }
}
*/

var out3 = JSON.stringify(json, ['key1', 'key2', 'key3', 'key4'])
/*
out3 = {
    key1: "Value for key1 in parent",
    key2: {
        key3: "Value for key3 in child",
        key4: "Value for key4 in child" // Both key4 returned
    },
    key4: "Value for key4 in parent" // Both key4 returned
}
*/
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