Muh*_*gan 6 javascript typescript
我有一个对象,我想将此对象的简化版本发送到服务器.
{
"fullName": "Don Corleone",
"actor": {
"actorId": 2,
"name": "Marlon",
"surname": "Brando",
"description": "Marlon Brando is widely considered the greatest movie actor of all time... ",
"heroList": [],
"photo": "C:\\projects\\files\\actor\\1532955376934.png"
},
"heroProfilePhoto": "data:image/png;base64,/9j/...
"production": {
"title": "The Godfather",
"imdbRate": 9.2,
"genre": "8",
"releaseDate": "1972-03-23T21:00:00.000Z",
"director": "Francis Ford Coppola",
"writer": "Mari Puzo",
"detail": "The aging patriarch of an organized crime dynasty transfers control of his clandestine empire to his reluctant son."
}
}"
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我有两个问题::
1)是否有可能提取像这样用替代品参数的JSON.stringify() ?
{
"fullName": "Don Corleone",
"actor": {
"actorId": 2
}
}"
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2)至少我可以提取像这样用替代品参数的JSON.stringify() ?
{
"fullName": "Don Corleone",
"actor": {
"actorId": 2,
"name": "Marlon",
"surname": "Brando",
"description": "Marlon Brando is widely considered the greatest movie actor of all time... ",
"heroList": [],
"photo": "C:\\projects\\files\\actor\\1532955376934.png"
},
}"
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当我这样使用时,没关系:
JSON.stringify(hero, ['fullName']) 结果 - > "{"fullName":"Don Corleone"}"
但是这个 :
JSON.stringify(hero, ['fullName', 'actor']) 结果 - > "{"fullName":"Don Corleone","actor":{}}"
为什么演员财产是空的?
JSON.stringify要求您传递您想要返回的所有数据.'actor'靠自己是不够的.
你要:
JSON.stringify(hero, ['fullName', 'actor', 'actorId'])
编辑
所以我做了一些测试,我很好奇如果actorId在父对象中也存在会发生什么,结果是在.
actorId在actorId存在于actor对象内部和父对象内部的情况下,JSON.stringify()返回两个字段.如果您不希望出现这种情况,则必须根据需要创建更复杂的函数,并将其传递给JSON.stringify(),如此处所述
以下是一些例子:
var json = {
key1: "Value for key1 in parent",
key2: {
key3: "Value for key3 in child",
key4: "Value for key4 in child"
},
key4: "Value for key4 in parent"
}
var out1 = JSON.stringify(json, ['key1', 'key3'])
/*
out1 = {
key1: "Value for key1 in parent"
} // No key3!
*/
var out2 = JSON.stringify(json, ['key1', 'key2', 'key3'])
/*
out2 = {
key1: "Value for key1 in parent",
key2: {
key3: "Value for key3 in child"
}
}
*/
var out3 = JSON.stringify(json, ['key1', 'key2', 'key3', 'key4'])
/*
out3 = {
key1: "Value for key1 in parent",
key2: {
key3: "Value for key3 in child",
key4: "Value for key4 in child" // Both key4 returned
},
key4: "Value for key4 in parent" // Both key4 returned
}
*/
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