在python数组中排序日期

Question

如何在python 2.4上对下面的日期数组进行排序

 timestamps = ['2011-06-2', '2011-08-05', '2011-02-04', '2010-1-14', '2010-12-13', '2010-1-12', '2010-2-11', '2010-2-07', '2010-12-02', '2011-11-30', '2010-11-26', '2010-11-23', '2010-11-22', '2010-11-16']

Answer 1

>>> import datetime
>>> dates = [datetime.datetime.strptime(ts, "%Y-%m-%d") for ts in timestamps]
>>> dates.sort()
>>> sorteddates = [datetime.datetime.strftime(ts, "%Y-%m-%d") for ts in dates]
>>> sorteddates
['2010-01-12', '2010-01-14', '2010-02-07', '2010-02-11', '2010-11-16', '2010-11-
22', '2010-11-23', '2010-11-26', '2010-12-02', '2010-12-13', '2011-02-04', '2011
-06-02', '2011-08-05', '2011-11-30']

Answer 2

sorted(timestamps, key=lambda d: map(int, d.split('-')))

Answer 3

只是这样做：

timestamps.sort()

结果：

['2010-1-12',
 '2010-1-14',
 '2010-11-16',
 '2010-11-22',
 '2010-11-23',
 '2010-11-26',
 '2010-12-02',
 '2010-12-13',
 '2010-2-07',
 '2010-2-11',
 '2011-02-04',
 '2011-06-2',
 '2011-08-05',
 '2011-11-30']

订单年-月-日允许这种排序，因为在经过时间时，日期在一个月之前更改，而月份在一年之前更改。

这就像一个数字：当递增1时，单位数字（最右边的数字）在十位数之前改变，而后者在百位数之前改变。

并且有一个事实是sort（）从左到右处理：如果要精确排序的两个字符串中某个位置的字符相同，则它将检查以下位置的两个字符串中的两个字符，以确定哪个字符是从逻辑上讲。

加上'0'<'1'为True，'1'<'2'为True等事实

Answer 4

>>> import time
>>> timestamps = ['2011-06-2', '2011-08-05', '2011-02-04', '2010-1-14', '2010-12-13', '2010-1-12', '2010-2-11', '2010-2-07', '2010-12-02', '2011-11-30', '2010-11-26', '2010-11-23', '2010-11-22', '2010-11-16']
>>> timestamps.sort(key=lambda x: time.mktime(time.strptime(x,"%Y-%m-%d")))
>>> timestamps
['2010-1-12', '2010-1-14', '2010-2-07', '2010-2-11', '2010-11-16', '2010-11-22', '2010-11-23', '2010-11-26', '2010-12-02', '2010-12-13', '2011-02-04', '2011-06-2', '2011-08-05', '2011-11-30']